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Norma-Jean [14]
3 years ago
7

an object of mass 300kg is observed to accelerate at the rate of 4 m/s^2. Caculate the force required to produce this accelerati

on
Mathematics
1 answer:
icang [17]3 years ago
4 0

Answer:

1200 N

Step-by-step explanation:

Newton's second law:

F = ma

F = (300 kg) (4 m/s²)

F = 1200 N

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Scientific notation
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Answer:

51,760

Step-by-step explanation:

Move the decimal place 4 tens places to the right (Positively)

51,760

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Mr. warren has a bag of nails assorted lengths. he asks his sons paul and tim to sort them by length. paul pours 3/4 of the bag
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Answer:

Step-by-step explanation:

he has 1/4 remaining as he has only used 3/4

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3 years ago
Which equation is represented by the line
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3 years ago
The rate of transmission in a telegraph cable is observed to be proportional to x2ln(1/x) where x is the ratio of the radius of
sergij07 [2.7K]

Answer:

The value of x that gives the maximum transmission is 1/√e ≅0.607

Step-by-step explanation:

Lets call f the rate function f. Note that f(x) = k * x^2ln(1/x), where k is a positive constant (this is because f is proportional to the other expression). In order to compute the maximum of f in (0,1), we derivate f, using the product rule.

f'(x) = k*((x^2)'*ln(1/x) + x^2*(ln(1/x)')) = k*(2x\,ln(1/x)+x^2*(\frac{1}{1/x}*(-\frac{1}{x^2})))\\= k * (2x \, ln(1/x)-x)

We need to equalize f' to 0

  • k*(2x ln(1/x) - x) = 0 -------- We send k dividing to the other side
  • 2x ln(1/x) - x = 0 -------- Now we take the x and move it to the other side
  • 2x ln(1/x) = x -- Now, we send 2x dividing (note that x>0, so we can divide)
  • ln(1/x) = x/2x = 1/2 -------  we send the natural logarithm as exp
  • 1/x = e^(1/2)
  • x = 1/e^(1/2) = 1/√e ≅ 0.607

Thus, the value of x that gives the maximum transmission is 1/√e.

7 0
3 years ago
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