Answer:
1. x² + 3x - 5 = 0
2. x² - x = 3 x + 7
4. 7x² + 14x = 0
Step-by-step explanation:
A Quadratic equation takes the form;
ax² + bx + c = 0
a, b, c are constants and a cannot be 0.
Options 1 fits this;
x² + 3x - 5 = 0
Option 2 fits this as well;
x² - x = 3 x + 7
x² -x - 3x - 7 = 0
x² - 4x - 7 = 0
Option 4 fits this as well if c = 0.
7x² + 14x + 0 = 0
If I did my math correctly I believe your answer will be C. :)
<span>(Y-3)^2 = 4y -12 <=> Y^2 - 6Y + 9 = 4y - 12 <=> 4y = Y^2 - 6Y + 21 <=> y = (Y^2 - 6Y + 21)/4. Solving the equation for y means that we have to express y relative to the other quantities in the equation.</span>
