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iren [92.7K]
4 years ago
11

Which transformation shows that the two given circles are similar? Circle A -- center(2, 0), radius 8 Circle A' -- center(-1, 5)

, radius 3
Mathematics
2 answers:
Goryan [66]4 years ago
5 0
Translate Circle A (x-3, y+5) and then dilate by a scale factor of 3/8 or 0.375
yawa3891 [41]4 years ago
5 0

Answer:

Step-by-step explanation:

One circle A with the center (2, 0) is transformed to a new point A' (-1, 5) means a circle is shifted to A' with new coordinates.

Therefore transformation done will be A [(2-x), (0-y)]

Here 2 - x = -1

-x = -2 - 1 = -3

x = 3

and 0-y = 5

y = -5

Therefore the transformation done is [(x - 3), (y +5)].

Now we see that the radius of the new circle is changed. Therefore new circle is enlarged with a scale factor of 3/8 = ( new radius/old radius)

So we conclude that a circle A is transformed to A' with [(x -3), (y + 5)]

and then enlarged by a scale factor of 3/8.

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Which terms are like terms in the expression 5x + 9 + (-7x)
Veronika [31]

Answer:

5x and -7x

Step-by-step explanation:

they both end in the variable "x"

7 0
3 years ago
A number is randomly selected from {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. A is represented by the event that the number picked is grea
fomenos
P(A) = P(8) + P(9) + P(10) = 3/10 so P(A complement) = 1 - P(A) = 1 - 3/10 = 7/10 - D
7 0
4 years ago
Read 2 more answers
Help solve 4 and 5 please
Sloan [31]

Answer:

Step-by-step explanation:

4). a). If the diagonals of a parallelogram are congruent, then it must be a RECTANGLE.

b). If the diagonals of a parallelogram are perpendicular, then it must be a SQUARE.

c). If the diagonals of a parallelogram bisect the angles of the parallelogram, then it must be a RHOMBUS.

d). If the diagonals of a parallelogram are perpendicular and congruent, then it must be a SQUARE.

e). If a parallelogram has four congruent sides, then it must be a SQUARE.

5). Given quadrilateral SELF is a rhombus.

a). All sides of a rhombus are equal,

   Therefore, ES = EL = 25

b). Diagonals of a rhombus bisects the opposite angles,

   Therefore, m∠ELS = m∠FLS

    3x - 2 = 2x + 7

    3x - 2x = 7 + 2

    x = 9

c). Diagonals of the rhombus bisect the opposite angles, and adjacent angles are supplementary.

m∠ELF = 2(m∠ELS) = 2(2y - 9)

m∠LES = 2(m∠LEF) = 2(3y + 9)

And 2(2y - 9) + 2(3y + 9) = 180

(2y - 9) + (3y + 9) = 90

5y = 90

y = 18  

6 0
3 years ago
A clothing manufacturer uses the model a=f+4−−−−√−36−f−−−−−√ to estimate the amount of fabric to order from a mill. In the formu
Anit [1.1K]

Questions:

A clothing manufacturer uses the model a = √(f + 4) - √(36 - f) to estimate the amount of fabric to order from a mill. In the formula, a is the number of apparel items (in hundreds) and f is the number of units of fabric needed. If 400 apparel items will be manufactured , how many units of fabric should be ordered?

Answer:

32 units of fabrics

Step-by-step explanation:

Given

a = \sqrt{f + 4} - \sqrt{36 - f}

Required

Find f when a  = 4

Substitute 4 for a

4 = \sqrt{f + 4} - \sqrt{36 - f}

Rewrite as:

\sqrt{36 - f} + 4 = \sqrt{f + 4}

Square both sides

(\sqrt{36 - f} + 4)^2 = (\sqrt{f + 4})^2

(\sqrt{36 - f} + 4)^2 = f + 4

36 - f + 8\sqrt{36 - f} + 16 = f + 4

Collect Like Terms

8\sqrt{36 - f}= f +f+ 4 - 36 -16

8\sqrt{36 - f}= 2f -48

Divide through by 2

4\sqrt{36 - f}= f -24

Square both sides

16(36-f) = (f - 24)^2

16(36-f) = f^2 - 48f + 576

576-16f = f^2 - 48f + 576

-16f = f^2 - 48f

Collect like terms

f^2 - 48f + 16f = 0

f^2 -32f = 0

Factorize

f(f - 32) = 0

f = 0 or f = 32

f can not be 0 because some units must be ordered.

So, f = 32

6 0
3 years ago
Someone pls help me i really need this
lukranit [14]
Y=1\2x.
hopes this helps you
5 0
3 years ago
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