x+y=10
x-y=8, x=y+8
y+8+y=10
2y=2
y=1
So, x=10-y=10-1=9.
Numbers Would be 9 and 1.
We can find the side length of square 3 by dividing by 4, which is 9.
Then, we find the side length of square 2 by dividing it by 4, which is 12.
To find the AREA of square 1, we do a^2+b^2=c^2. This is basically adding up area of square 1 and square 2 to get square 3.
a^2+b^2=c^2
9^2+12^2=c^2
81+144=225
So the area is 225 units.
X by its self is always 1x
1x+8=-15 you have to get rid of 8 by subtracting on both sides
1x=-23 now get rid of 1 by dividing on both sides
x=-23
Answer:
Written out the equation would look like f(x) = 55(1.06)^x
The graph would look something like the attached picture. (It intercepts with the y-axis at 55).
Answer:
area of a square is S^2
s = 5n^4
area = (5n^4)^2 = 25n^8
Step-by-step explanation:
