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denpristay [2]
2 years ago
12

3x + 2y = 3 / 2x + 3y = 2

Mathematics
2 answers:
kvasek [131]2 years ago
8 0

Answer:

x = 1 , y = 0

Step-by-step explanation:

3x + 2y = 3 ------> (1)

2x + 3y = 2 --------> (2)

(1) × 2

2 × ( 3x + 2y = 3 )

6x + 4y = 6 -------> (3)

(2) × 3

3 × ( 2x + 3y = 2 )

6x + 9y = 6 ------> (4)

(4) - (3)

6x + 9y - ( 6x + 4y ) = 6 - 6

6x + 9y -  6x - 4y = 0

5y = 0

y = 0

If y = 0,

2x + 3y = 2

2x + 3y = 2

2x + 3 × 0 = 2

2x + 0  = 2

2x = 2

x = 1

Hope this helps you :-)

Let me know if you have any other questions :-)

stiks02 [169]2 years ago
6 0

Answer:

Step-The solution of the set of equations 3x-2y=3 and 2x+3y=2 has to be determined.

3x-2y=3 ...(1)

2x+3y=2 ...(2)

3*(1) - 2*(2)

=> 9x - 6y - 4x - 6y = 9 - 4

=> 5x = 5

=> x = 1

Substituting x = 1 in (1)

3 - 2y...

by-step explanation:

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Step-by-step explanation:

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3 years ago
A manufacturer has been selling 1000 flat-screen TVs a week at $500 each. A market survey indicates that for A manufacturer has
luda_lava [24]

Answer:

a) Demand function: q=6000-10\cdot p

b) The rebate should be of $200, so the sale price becomes $300 per unit.

c) The rebate should be of $150, so the sale price becomes $350 per unit.

Step-by-step explanation:

a) In this case, we have a known point of the demand function (1000 units sold at $500), and the slope of a linear function (increase by 100 units fora decrease in $10).

We can express the demand function (linear) as:

q=b+m\cdot p

To calculate the slope m, we use:

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To calculate b, we use the known point and the calculated slope:

q=b+m\cdot p\\\\b=q-m\cdot p=1000-(-10)\cdot (500)=1000+5000=6000

Then the demand function is:

q=6000-10\cdot p

b) The revenue can be expressed as:

R=q\cdot p = (6000-10p)\cdot p=6000p-10p^2

To maximize, we can derive and equal to zero

dR/dp=6000-2*10p=0\\\\20p=6000\\\\p=300

The rebate should be of $200, so the sale price becomes $300 per unit.

c) If we take into account the cost, we have that

R=q\cdot p-C=(6000p-10p^2)-(68000+100q)\\\\R=(6000p-10p^2)-(68000+100(6000-10p))\\\\R=6000p-10p^2-(68000+600000-1000p)\\\\R=-10p^2+7000p-668000

To maximize, we can derive and equal to zero

dR/dp=-20p+7000=0\\\\p=7000/20=350

The rebate should be of $150, so the sale price becomes $350 per unit.

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Help me pls... ....
musickatia [10]

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therefore,

2.2 liters = 2.2×1000 = 2200 milliliters

A5

again, 1 liter = 1000 milliliters

therefore

1 milliliter = 1/1000 liter

670 milliliters = 670 × 1/1000 liter = 670/1000 liter =

= 0.67 liter

B1

1 kg (kilogram) = 1000 grams ("kilo" means 1000).

we have 3 layers.

each layer weighs (cake plus icing)

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3 layers then weigh

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area is 110 m².

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