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Sedaia [141]
3 years ago
10

Steven can jog 14 miles in 2 hours at this rate how many miles 3 dragon 1/4 of an hour

Mathematics
1 answer:
kaheart [24]3 years ago
4 0

Answer:

1.75 miles

Step-by-step explanation:

14*1/4/2

=7/4

=1.75 miles

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Of 15 possible​ books, you plan to take 6 with you on vacation. How many different collections of 6 books can you​ take?
Mekhanik [1.2K]

Answer:

5005

Step-by-step explanation:

6 C 15

(6, 15)

15! / (6! x 9!)

The answer is 5005

C is just a way to say the order the books are picked in is random and ! means factorial. Factorial is when you multiply all the previous numbers up to the number it is. For example, 5! = 1 x 2 x 3 x 4 x 5 and 2! = 1 x 2

6 0
3 years ago
How do u stop whaching adds if ur new
Alexxx [7]

Answer:

to be honest I dont know

Step-by-step explanation:

I dont know  how.

6 0
3 years ago
Read 2 more answers
6 $44 is shared between David, Jo and Mary in the ratio 2:3:5<br> How much does each receive?
OverLord2011 [107]

Answer:

David=$8.8

Jo=$13.2

Mary=$22

Step-by-step explanation:

2+3+5=10

44/10=4.4

David=4.4x2=$8.8

Jo=4.4x3=$13.2

Mary=4.4x5=$22

8.8+13.2+22=44

8 0
3 years ago
What are the solutions of the system y=x^2+3x-4 y=2x+2
ra1l [238]
Hope this would help you

8 0
4 years ago
Does anyone know how to do this?? Help please!!!!
Doss [256]

Answer:

When we have a rational function like:

r(x) = \frac{x + 1}{x^2 + 3}

The domain will be the set of all real numbers, such that the denominator is different than zero.

So the first step is to find the values of x such that the denominator (x^2 + 3) is equal to zero.

Then we need to solve:

x^2 + 3 = 0

x^2 = -3

x = √(-3)

This is the square root of a negative number, then this is a complex number.

This means that there is no real number such that x^2 + 3 is equal to zero, then if x can only be a real number, we will never have the denominator equal to zero, so the domain will be the set of all real numbers.

D: x ∈ R.

b) we want to find two different numbers x such that:

r(x) = 1/4

Then we need to solve:

\frac{1}{4} = \frac{x + 1}{x^2 + 3}

We can multiply both sides by (x^2 + 3)

\frac{1}{4}*(x^2 + 3) = \frac{x + 1}{x^2 + 3}*(x^2 + 3)

\frac{x^2 + 3}{4} = x + 1

Now we can multiply both sides by 4:

\frac{x^2 + 3}{4}*4 = (x + 1)*4

x^2 + 3 = 4*x + 4

Now we only need to solve the quadratic equation:

x^2 + 3 - 4*x - 4 = 0

x^2 - 4*x - 1 = 0

We can use the Bhaskara's formula to solve this, remember that for an equation like:

a*x^2 + b*x + c = 0

the solutions are:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

here we have:

a = 1

b = -4

c = -1

Then in this case the solutions are:

x = \frac{-(-4) +- \sqrt{(-4)^2 - 4*1*(-1)} }{2*(1)} = \frac{4 +- 4.47}{2}

x = (4 + 4.47)/2 = 4.235

x = (4 - 4.47)/2 = -0.235

5 0
3 years ago
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