I'd be more than happy to do all of that, but I can't even start
until I see YOUR picture of the problem. That will show me
if circle-P and circle-q are overlapping, just touching, separate
from each other, same size, different sizes, their radii, and where
the points J and K are. THOSE are the little things I need to know
in order to get started.
You want to know the distance between J and K, but you haven't
given us one single distance or size of anything in the problem ...
nothing at all to work with. That right there makes it impossible.
Answer:
51 square units
Step-by-step explanation:
Area of a parallelogram = base x height
⇒ area = 4 x 3 = 12 square units
Area of a rectangle = width x length
width = √(2² + 3²) = √13
length = √(9² + 6²) = √117
area = √13 x √117 = 39 square units
Total area = 12 + 39 = 51 square units
Answer:
x = 
Step-by-step explanation:
We know that;
The triangle is isosceles, and the hypotenuse is x, the un-labeled side is 5.
Therefore we can say;
5² + 5² = x²
25 + 25 = x²
50 = x²
= x
We can simplify this further;
=
=
Hope this helps!
Answer:
4:5
Step-by-step explanation:
Binh's = 40
Davina's = 50
40:50 = 4:5
Answer:
Area = 3.3998
Perimeter = 2.9
Step-by-step explanation:
A method for calculating the area of a triangle when you know the lengths of all three sides.
Let a,b,c be the lengths of the sides of a triangle. The area is given by:
Area = √ p ( p − a ) ( p − b ) ( p − c )
where p is half the perimeter, or
a + b + c / 2
p = 1.7 + 1.7 + 2.4 / 2 = 5.8 / 2 = 2.9
a = Area = 3.3998
Heron was one of the great mathematicians of antiquity and came up with this formula sometime in the first century BC, although it may have been known earlier. He also extended it to the area of quadrilaterals and higher-order polygons.
