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2 years ago

Need help and NO LINKS!!! Special Right Triangles (Radical Answers)

Mathematics

1 answer:

Nata [24]2 years ago

8 0

Answer:

x = $5\sqrt{2}$

Step-by-step explanation:

We know that;

The triangle is isosceles, and the hypotenuse is x, the un-labeled side is 5.

Therefore we can say;

5² + 5² = x²

25 + 25 = x²

50 = x²

$\sqrt{50}$ = x

We can simplify this further;

$\sqrt{25} * \sqrt{2}$ = $\sqrt{50}$

$5\sqrt{2}$ = $\sqrt{50}$

Hope this helps!

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postnew [5]

Answer:

(2)

Step-by-step explanation:

slope:-1/2

y-intercept:1 (because the function passes (0,1))

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2 years ago

A new LED light bulb uses 10 watts of power. Since energy = power × time , then the energy used for this light bulb can be found

sergiy2304 [10]

9514 1404 393

Answer:

150 Wh

Step-by-step explanation:

We know the energy per bulb is 10 Wh per hour, so the total energy used by 3 bulbs in 5 hours is ...

(10 Wh/(bulb·hour))×(3 bulbs)×(5 hours) = 10·3·5 Wh = 150 Wh

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2 years ago

What are the leading coefficient and degree of the polynomial? 3u+12u'-7u* +1

xxTIMURxx [149]

Answer:

See explanation

Step-by-step explanation:

Assuming the given polynomial is

$3u + 12 {u}^{2} - 7 {u}^{3} + 1$

We then rewrite in decreasing powers of u, to get:

$- 7 {u}^{3} + 12 {u}^{2} + 3u + 1$

The leading term is

$- 7 {u}^{3}$

The leading coefficient is the coefficient of the leading term.

The leading coefficient is -7.

6 0

3 years ago

6. If you draw 35 lines on a piece of paper so that no two lines are parallel to each

umka2103 [35]

The point of intersection is the point where lines intersect.

There will be 595 intersections for 35 lines, where no 3 lines are concurrent.

Given

$n = 35$ --- the number of lines

$d = 3$ --- no three lines are concurrent

When no three line are concurrent, it means that no three lines meet at the same point.

So, the sequence of intersection is:

0 intersection for 1 line
1 intersection for 2 lines
3 intersections for 3 lines
6 intersections for 4 lines

Following the above sequence, the number of intersections for n lines is:

$n_k = \frac{n \times (n - 1)}{2}$

In this case, $n = 35.$

So, we have:

$n_k = \frac{35 \times (35 - 1)}{2}$

$n_k = \frac{35 \times 34}{2}$

$n_k = 35 \times 17$

$n_k = 595$

Hence, there will be 595 intersections for 35 lines, where no 3 lines are concurrent.

Read more about lines of intersections at:

brainly.com/question/22368617

7 0

2 years ago

Read 2 more answers

The sum of two.number is.24. the.sun.of the square.of the two.nunber is 306. what is the product.of the two.number

tresset_1 [31]

A) x + y = 24
B) x^2 + y^2 = 306

A) x = 24 -y
Then substituting this into B)
(24 - y)^2 +y^2 = 306
576 -48y +y^2 + y^2 = 306
2 y^2 -48y + 270 = 0
x1 = 15
x2 = 9

3 0

3 years ago