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HACTEHA [7]
4 years ago
6

20. Average year-after-year conditions are to__________as day-to-day atmospheric conditions are to

Mathematics
1 answer:
Alenkasestr [34]4 years ago
4 0
Year after year conditions refer to climate. Climate is based on an average of overall weather conditions. It can aid Meteorologists in long and short term weather predictions based on past and present weather conditions. Day to day atmospheric conditions refer to weather. 
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Find the indicated side of the<br> triangle.<br> b<br> 7<br> 45°<br> a<br> b = [?]VO
vodka [1.7K]

Answer:

7√2

Step-by-step explanation:

Thank to the give angle we can say that the two legs are congruent

b = \sqrt{7^2 + 7^2} = \sqrt{49+49} = \sqrt{98}

98/2 = 49

49/7 = 7

7/7 = 1

98 = 7^2 x 2

√98 = 7√2

8 0
3 years ago
I need help with this please
Roman55 [17]

Answer:

the answer is 80 degrees. angle between 2 parrael line is same

6 0
3 years ago
Read 2 more answers
There is a bag with only milk and dark chocolates. The probability of randomly choosing a dark chocolate is 5 12 . There are 40
Maksim231197 [3]

Answer:

There must be 96 milk chocolates.

Step-by-step explanation:

If you take the original ratio, 5:12, and replace the 5 with 40, you'd discover that 40 divided by 5 is 8. So what do you do? You multiply the 12 by 8 to get 96 so now the ratio is 40:96.

5 0
3 years ago
Find the slope of the line 8x – 4y = 8\ (hint: find 2 points; then use the slope formula)
Vera_Pavlovna [14]
8x - 4y = 8

-4y = -8x + 8

y = -8x/-4 + 8/-4

y = 2x - 2,  comparing to y = mx + c, slope m = 2

Slope = 2.
6 0
3 years ago
Can someone help me please
saul85 [17]
Using the Law of Sines  (sina/A=sinb/B=sincC for any triangle)

sinc/28=sin90/53  (sin90=1)  multiply both sides by 28

sinc=28/53  take the inverse of sin (arcsin) of both sides

c=arcsin(28/53)°

c≈31.89°  (to nearest hundredth of a degree)

So it is obvious that they rounded to nearest tenth of a degree

c≈31.9°
5 0
3 years ago
Read 2 more answers
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