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fredd [130]
3 years ago
15

Luis le dice a su amiga: "Yo tengo ahora el triple de edad que tú tenías, cuando yo tenía la edad que tú tienes ahora". Si entre

los dos suman 50 años, ¿cuántos tiene cada uno?
Mathematics
1 answer:
g100num [7]3 years ago
6 0

Answer:

Luis tiene 30 años de edad y su amiga tiene 20 años edad.

Step-by-step explanation:

Cuando Luis tenia 20 años de edad (hace 10 años), su amiga tenia solamente 10 años de edad. Si multiplicamos 10 x 3 nos da como resultado 30, que es la edad actual de Luis.

L + A = 50

3(A - x) = L

L = 50 - A

3A - 3x = 50 - A

4A = 50 + 3x

en este punto podemos probar diferentes alternativas para x:

x = 5, entonces 4A = 50 + 15

A = 16.25 no es factible porque estamos buscando numeros enteros

x = 6, entonces 4A = 50 + 18

A = 17

al reemplazar, nos da una edad de 3(17 - 5) = 36 para Luis, pero 36 + 17 = 53

x = 8, entonces 4A = 50 + 24

A = 18.5 no es factible porque estamos buscando numeros enteros

x = 10, entocnes 4A = 50 + 30

A = 20

al reemplazar, nos da una edad de 3(20 - 10) = 30 para Luis, y 30 + 20 = 50

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LiRa [457]

Answer:

  1/63

Step-by-step explanation:

There are a couple of ways to do this.

<h3>1) </h3>

Look for the GCF of the numerators when a common denominator is used.

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<h3>2) </h3>

Use Euclid's algorithm. If the remainder from division of the larger by the smaller is zero, then the smaller is the GCF; otherwise, the remainder replaces the larger, and the algorithm repeats.

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The GCF is 1/63.

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* The quotient is 28/27 = 1 +1/27 = 1 +(1/27)(3/7)/(3/7) = 1 +(1/63)/(3/7) or 1 with a remainder of 1/63.

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<em>Additional comment</em>

3/7 = (1/63) × 27

4/9 = (1/63) × 28

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