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fredd [130]
3 years ago
15

Luis le dice a su amiga: "Yo tengo ahora el triple de edad que tú tenías, cuando yo tenía la edad que tú tienes ahora". Si entre

los dos suman 50 años, ¿cuántos tiene cada uno?
Mathematics
1 answer:
g100num [7]3 years ago
6 0

Answer:

Luis tiene 30 años de edad y su amiga tiene 20 años edad.

Step-by-step explanation:

Cuando Luis tenia 20 años de edad (hace 10 años), su amiga tenia solamente 10 años de edad. Si multiplicamos 10 x 3 nos da como resultado 30, que es la edad actual de Luis.

L + A = 50

3(A - x) = L

L = 50 - A

3A - 3x = 50 - A

4A = 50 + 3x

en este punto podemos probar diferentes alternativas para x:

x = 5, entonces 4A = 50 + 15

A = 16.25 no es factible porque estamos buscando numeros enteros

x = 6, entonces 4A = 50 + 18

A = 17

al reemplazar, nos da una edad de 3(17 - 5) = 36 para Luis, pero 36 + 17 = 53

x = 8, entonces 4A = 50 + 24

A = 18.5 no es factible porque estamos buscando numeros enteros

x = 10, entocnes 4A = 50 + 30

A = 20

al reemplazar, nos da una edad de 3(20 - 10) = 30 para Luis, y 30 + 20 = 50

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The table shows the viscosity of an oil as a function of temperature. Identify a quadratic model for the viscosity, given the te
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Answer:

The viscosity at 140°C is predicted to be 7.2

Step-by-step explanation:

The function that model the relationship between viscosity and temperature = Quadratic model

The general form of a quadratic equation is y = a·x² + b·x + c

Therefore, we have;

When y = 10.8, x = 110, which gives;

10.8 = a·110² + b·110 + c = 12100·a + 110·b + c

10.8 = 12100·a + 110·b + c

When y =8.2, x = 130

8.2 = a· 130² + b· 130 + c = 16900·a + 130·b + c

8.2 = 16900·a + 130·b + c

When y = 160, x = 5.8

5.8 = a·160² + b·160 + c = 25600·a + 160·b + c

5.8 = 25600·a + 160·b + c

The three equations above can be listed as follows;

10.8 = 12100·a + 110·b + c

8.2 = 16900·a + 130·b + c

5.8 = 25600·a + 160·b + c

Solving using matrices gives;

\begin{bmatrix}12100 & 110 & 1\\ 16900 & 130 & 1\\ 25600 & 160 & 1\end{bmatrix} \begin{bmatrix}a\\ b\\ c\end{bmatrix} = \begin{bmatrix}10.8\\ 8.2\\ 5.8\end{bmatrix}

\begin{bmatrix}a\\ b\\ c\end{bmatrix} = -\dfrac{1}{3000}\begin{bmatrix}3 & -5 & 2\\ -867 & 1350 & -480\\ 62400 & -88000 & 28600\end{vmatrix} \begin{bmatrix}10.8\\ 8.2\\ 5.8\end{bmatrix}

From which we have;

a = 0.001, b = -0.37, c = 39.4

Substituting gives;

y = 0.001·x² - 0.37·x + 39.4

When x = 140

y = 0.962·140² - 0.37·140 + 39.4= 7.2

The viscosity at 140°C = 7.2.

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X=y=29 divided by square root of 2.
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What is the value of x?
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Answer:

x=71

Step-by-step explanation:

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3 years ago
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