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fredd [130]
3 years ago
15

Luis le dice a su amiga: "Yo tengo ahora el triple de edad que tú tenías, cuando yo tenía la edad que tú tienes ahora". Si entre

los dos suman 50 años, ¿cuántos tiene cada uno?
Mathematics
1 answer:
g100num [7]3 years ago
6 0

Answer:

Luis tiene 30 años de edad y su amiga tiene 20 años edad.

Step-by-step explanation:

Cuando Luis tenia 20 años de edad (hace 10 años), su amiga tenia solamente 10 años de edad. Si multiplicamos 10 x 3 nos da como resultado 30, que es la edad actual de Luis.

L + A = 50

3(A - x) = L

L = 50 - A

3A - 3x = 50 - A

4A = 50 + 3x

en este punto podemos probar diferentes alternativas para x:

x = 5, entonces 4A = 50 + 15

A = 16.25 no es factible porque estamos buscando numeros enteros

x = 6, entonces 4A = 50 + 18

A = 17

al reemplazar, nos da una edad de 3(17 - 5) = 36 para Luis, pero 36 + 17 = 53

x = 8, entonces 4A = 50 + 24

A = 18.5 no es factible porque estamos buscando numeros enteros

x = 10, entocnes 4A = 50 + 30

A = 20

al reemplazar, nos da una edad de 3(20 - 10) = 30 para Luis, y 30 + 20 = 50

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s(t) = 0.29t2 − t + 25 gallons per year (0 ≤ t ≤ 7), where t is time in years since the start of 2007. Use a Riemann sum with n
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Answer: The answer is 300 gallons.

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To calculate that area, we divide it into a number of rectangles with one point touching the curve. The curve has a closed interval [a,b] that can be subdivided into n subintervals, each having a width of Δx_{k} = \frac{b-a}{n}

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