The length and the width of the rectangle are 20 and 14 inches respectively
<h3>How to find the length and width?</h3>
The given parameters are:
Length = 6 + Width
Perimeter = 68 inches
The perimeter of a rectangle is calculated as:
Perimeter = 2 * (Length + Width)
So, we have:
2 * (Length + Width) = 68
Divide both sides by 2
Length + Width = 34
Substitute Length = 6 + Width in Length + Width = 34
6 + Width + Width = 34
Evaluate the like terms
2 * Width = 28
Divide both sides by 2
Width = 14
Substitute Width = 14 in Length = 6 + Width
Length = 6 + 14
Evaluate
Length = 20
Hence, the length and the width of the rectangle are 20 and 14 inches respectively
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Six and eighty hundred thirty seven thousandths
-3
Solution,
Let the points be A and B
A(-3,2)------->( X1,y1)
B(-2,5)------>( x2,y2)
Answer:
x = 44
Step-by-step explanation:
sqrt(x+5) -3 =4
Add 3 to each side
sqrt(x+5) -3+3 =4+3
sqrt(x+5) =7
Square each side
(sqrt(x+5))^2 =7^2
x+5 = 49
Subtract 5 from each side
x+5-5 = 49-5
x=44
Answer:
0.12
because 3/5 of 0.2 is 0.12
u probably shouldn’t trust me im dum
Step-by-step explanation: