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viktelen [127]
3 years ago
10

Which two points satisfy y = -x2 + 2x + 4 and x + y = 4? A. (0, 4) and (4, 0) B. (0, 4) and (3, 1) C. (7, -3) and (0, 4) D. (7,

-3) and (4, 0)

Mathematics
1 answer:
svetoff [14.1K]3 years ago
4 0
It’s B.) (0,4) and (3,1). I hope this helps!!!

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enyata [817]

Answer:

<h2>19/3</h2>

Step-by-step explanation:

Given the expression 3\left(q+\dfrac43\right) = 23, we are to find the value of q;

3\left(q+\dfrac43\right) = 23\\on\ expansion\\\\3q + 4/3(3) = 23\\\\3q+4 = 23\\\\subtract \ 4\ from \ both\ sides \ of \ the \ equation\\\\3q+4-4 = 23-4\\\\3q = 19\\\\Diviide \both\ sides \ by \ 3\\\\3q/3 = 19/3\\\\q = 19/3

Hence the value of q is 19/3

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3 years ago
Describe the domain and range of y = 2(4)x+ ³ +2.
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2 years ago
What is the input value for which f(x)=3​
777dan777 [17]
X=-3. The question is wanting to know that if y=3, what does x equal? Well the only y-value that has y=3 on this line is x=-3
7 0
3 years ago
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What is the vertex of the function?
egoroff_w [7]
<h2>Explanation:</h2><h2></h2>

Here you haven't provided any function, so I'll assume this one:

f(x)=3x^2-18x+33

This is a quadratic function whose graph represents a parabola. Any parabola has its vertex at the point:

V(x,y) \\ \\ \\ x=-\frac{b}{2a} \\ \\ y=f(-\frac{b}{2a}) \\ \\ \\ where: \\ \\ \\ f(x)=ax^2+bx+c \\ \\ \\ So: \\ \\ a=3 \\ \\ b=-18 \\ \\ c=33

Therefore:

x=-\frac{(-18)}{2(3)}=3 \\ \\ f(3)=3(3)^2-18(3)+33=27-54+33=6

Therefore, the vertex is:

\boxed{V(3,6)}

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4 years ago
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GREYUIT [131]
The slope here is -4
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4 years ago
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