PLEASE HELP, IT'S ARGENT!

Mathematics

1 answer:

ANTONII [103]2 years ago

7 0

Answer:

I'm guessing the right answer should be B

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What is the equation of the line in slope-intercept form?

Sunny_sXe [5.5K]

Answer:

(-2,5),(0,5),(-2,0)

Step-by-step explanation:

×- axis and y- axis

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2 years ago

A chocolate chip cookie recipe asks for three and one half times as much flour as chocolate chips. If one and three quarters cup

Ganezh [65]

3.5 times as much flour as chocolate chips....
f = 3.5c
f = 1 3/4 (or 1.75)

1.75 = 3.5c
1.75 / 3.5 = c
0.5 = c......chocolate chips needed would be 1/2 a cup

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2 years ago

What’s the answer and how solve

maks197457 [2]

Answer: it’s 2

Step-by-step explanation:

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3 years ago

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Write an equation in standard form of the hyperbola described.

marishachu [46]

Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.

$\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill$

$\begin{cases} h=0\\ k=0\\ a=2\\ c=4 \end{cases}\implies \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{b^2} \\\\\\ c^2=a^2+b^2\implies 4^2=2^2+b^2\implies 16=4+b^2\implies \underline{12=b^2} \\\\\\ \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{12}\implies \boxed{\cfrac{x^2}{4}-\cfrac{y^2}{12}}$

5 0

1 year ago

Find the area of the shaded region. Round to the nearest tenth.

AURORKA [14]

Answer:

3.5 square cm

Step-by-step explanation:

$Area \: of \: both \: squares \\ = {2}^{2} + {3}^{2} \\ = 4 + 9 \\ = 13 \: {cm}^{2} \\ \\ Area \: of \: both \: right \: \triangle s \\ = \frac{1}{2} \times (2 + 3) \times 2 + \frac{1}{2} \times3 \times 3 \\ = 5 \times 1+ 1.5 \times 3 \\ = 5 + 4.5 \\ = 9.5 \: {cm}^{2} \\ \\ Area \: of \:shaded \: region \\ = Area \: of \: both \: squares\\ - Area \: of \: both \: right \: \triangle s \\ = 13 - 9.5 \\ \purple { \boxed{ \bold{Area \: of \:shaded \: region = 3.5 \: {cm}^{2} }}}$

7 0

3 years ago