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sineoko [7]
3 years ago
15

Help me pleaseeeeeeeeee

Mathematics
2 answers:
katovenus [111]3 years ago
5 0
Answer:

9 3/5 - (-5 1/4)
garik1379 [7]3 years ago
4 0

Answer:

-5\frac{1}{4}+9\frac{3}{5} (top right)

Step-by-step explanation:

Hope this helps :)

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For what values of theta, °
Anna11 [10]

Answer:

Step-by-step explanation:

6 0
3 years ago
(1 ÷ x- 1)+(2÷ x+2)=(3÷2) solve and check for extraneous solutions
Sliva [168]
\frac{1}{x-1}+ \frac{2}{x+2}= \frac{3}{2}
\frac{1(x+2)}{(x-1)(x+2)}+ \frac{2(x-1)}{(x+2)(x-1)}= \frac{3(x-1)(x+2)}{2}
\frac{x+2+2(x-1)}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}
\frac{x+2+2x-1}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}
\frac{3x+1}{(x-1)(x+2)}= \frac{3(x^2+x-2)}{2}
\frac{}{(x-1)(x+2)}= \frac{3x^2+3x-6)}{2}
\frac{3x+1}{(x^2+x-2)}= \frac{3x^2+3x-6)}{2}
\frac{2(3x+1)}{2(x^2+x-2)}= \frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}
\frac{2(3x+1)}{2(x^2+x-2)}-\frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}=0
\frac{2(3x+1)-3x^2+3x-6}{2(x^2+x-2)}=0

this will be continued
5 0
4 years ago
(6-root 8)^2= a b root 2 where and are constants to be found.
lilavasa [31]

Answer:2.8284.

Step-by-step explanation:

7 0
3 years ago
Please show your work! :)))
Naddika [18.5K]

Answer:

-8 3/4

Step-by-step explanation:

1. Simplify it.

15 - 24 + 1 divided by 4

2. Divide.

15 - 24 + 1/4

3. Add and subtract.

-9 + 1/4

-8 3/4

3 0
3 years ago
In the figure,ABC is congruent to ADC . If the square ABCD is dilated by a factor of 2 to form A'B'C'D', what is the ratio of th
DaniilM [7]
In the figure,ABC is congruent to ADC . If the square ABCD is dilated by a factor of 2 to form A'B'C'D', the ratio of the area of A'B'C'D' to the area of ABCD is 1/2. Since the dilation is by a factor of 2, so the area of the A'B'C'D' should be smaller than the area of ABCD.
8 0
4 years ago
Read 2 more answers
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