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3 years ago

Agent Hunt is transferring classified files from the CIA

Mathematics

1 answer:

Delvig [45]3 years ago

6 0

Answer:

50MB.

Step-by-step explanation:

Its on Khan Academy lol. Good luck on your unit test!!!

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I need help I would really thank whoever answers this for me

Mars2501 [29]

To do these problems, you plug in the ‘n’ value given into the equation.

a. 6j - 3 : j = 4
6(4) - 3
24 - 3
21

b. 1/2b + 5 : b = 14
1/2(14) + 5
7 + 5
12

c. 8 + 4k : k = 3.5
8 + 4(3.5)
8 + 14
22

6 0

2 years ago

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Given RS = 6, ST = 3, and SL = 4, find SM.

NemiM [27]

A² + b² = c²
3² + 4² = c²
9 + 16 = c²
C² = 25
C = 5
so
SM = 5

7 0

3 years ago

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I need help in Math

never [62]

The answer is C.) y=2x+1 since the slope is going upward, and will match the scatter plot.

4 0

3 years ago

The vertices of a triangle ABC are A(7, 5), B(4, 2), and C(9, 2). What is measure of angle ABC? 30° 45° 56.31° 78.69°

GenaCL600 [577]

The measure of angle ABC is 45°

Explanation

Vertices of the triangle are: A(7, 5), B(4, 2), and C(9, 2)

According to the diagram below....

Length of the side BC (a) $=\sqrt{(4-9)^2+(2-2)^2}= \sqrt{25}= 5$

Length of the side AC (b) $= \sqrt{(7-9)^2 +(5-2)^2}= \sqrt{4+9}=\sqrt{13}$

Length of the side AB (c) $= \sqrt{(7-4)^2 +(5-2)^2} =\sqrt{9+9}=\sqrt{18}$

We need to find ∠ABC or ∠B . So using Cosine rule, we will get...

$cosB= \frac{a^2+c^2-b^2}{2ac} \\ \\ cos B= \frac{(5)^2+(\sqrt{18})^2-(\sqrt{13})^2}{2*5*\sqrt{18} }\\ \\ cosB= \frac{25+18-13}{10\sqrt{18}} =\frac{30}{10\sqrt{18}}=\frac{3}{\sqrt{18}}\\ \\ cosB=\frac{3}{3\sqrt{2}} =\frac{1}{\sqrt{2}}\\ \\ B= cos^-^1(\frac{1}{\sqrt{2}})= 45 degree$

So, the measure of angle ABC is 45°

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3 years ago

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-3(-2x+1)-x=3(-x+2)-1

olga55 [171]

Answer: I think it is 5 or 4

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2 years ago

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