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2 years ago

PLEASE PLEASE HELP 50 POINTS

Mathematics

1 answer:

Crank2 years ago

8 0

Answer:

The claim is " oreos are the most popular cookie at my house". The evidence is because you said that " oreos run out twice as fast as snickerdoodles." The reasoning is because my family eats twice as many oreos than snickerdoodles.

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What describes angle 5 and 6

astraxan [27]

Answer:

Your answer is B: Corresponding angles.

4 0

2 years ago

Read 2 more answers

Please help me figure this out.

xz_007 [3.2K]

Answer:

Quotient: x+7

Remainder: -2

Step-by-step explanation:

Divide the terms (x² ÷ x =x)↓

(x² + 11x + 26) ÷ (x + 4) =x

Subtract x² + 4x (You have to the sign if each term)

(x² + 11x + 26) ÷ (x + 4) =x

-x² - 4x

-------------------

7x + 26

Divide the terms (7x ÷ x = 7)

x² + 11x + 26) ÷ (x + 4) =x + 7

Multiply the quotient by the dividend (x + 4) × 7 = 7x+28

(x² + 11x + 26) ÷ (x + 4) =x

-x² - 4x

-------------------

7x + 26

7x + 28

------------------

= -2 Remainder

4 0

2 years ago

If AG + GH = 10, then may GH = AG + 10?

Natali [406]

Yes it will, they are the same value just in diff locations

7 0

2 years ago

heights for 16 year old boys are normally distributed with a mean if 68.3 in and a standard deviation of 2.9 in. find the z-scor

allsm [11]

Simple just decide pie by the universe multiplied bye the square rout of a f1 race car most likely leading too yes

6 0

2 years ago

Finding area of shaded sectors.

tekilochka [14]

Answer:

69.81 sq. m. (rounded to 2 decimal places)

Step-by-step explanation:

The sector of a circle is "part" or "portion" of a circle. The formula for the area of a sector is:

$A=\frac{\theta}{360}*\pi r^2$

Where

$\theta$ is the central angle

r is the radius

Given the figure, the arc is given as 80 degrees, but not the central angle of the shaded sector. But from geometry we know that the central angle and the intercepted arc have the same measure. So we can say:

$\theta = 80$

Also, the radius of the circle shown is 10 meters, so

r = 10

Now, we substitute in formula and find our answer:

$A=\frac{\theta}{360}*\pi r^2\\A=\frac{80}{360}*\pi (10)^2\\A=\frac{2}{9}*100\pi\\A=\frac{200\pi}{9}\\A=69.81$

Thus,

The area of the shaded sector is 69.81 sq. meters.

5 0

2 years ago