The true statement about the circle with center P is that triangles QRP and STP are congruent, and the length of the minor arc is 11/20π
<h3>The circle with center P</h3>
Given that the circle has a center P
It means that lengths PQ, PR, PS and PT
From the question, we understand that QR = ST.
This implies that triangles QRP and STP are congruent.
i.e. △QRP ≅ △STP is true
<h3>The length of the minor arc</h3>
The given parameters are:
Angle, Ф = 99
Radius, r = 1
The length of the arc is:
L = Ф/360 * 2πr
So, we have:
L = 99/360 * 2π * 1
Evaluate
L = 198/360π
Divide
L = 11/20π
Hence, the length of the minor arc is 11/20π
Read more about circle and arcs at:
brainly.com/question/3652658
#SPJ1
12,24,36,48,60,72,84,96,108
The scale has two sides:
The Left Hand Side (LHS) and the Right Hand Side (RHS).
Let the weight of the sphere be represented as s
Let the weight of the cube be represented as c
Let the LHS have the 5 spheres and 1 cube, represented as = (5s + 1c)
Let the RHS have the 2 spheres and 3 cubes, represented as = (2s + 3c)
If the cube c, weighs 150 gram, c = 150g
Since the scale is balanced, therefore the weights on the LHS would be equal to the weights on the RHS.
Therefore: (5s + 1c) = (2s + 3c), c = 150.
(5s + 1*150) = (2s + 3*150)
(5s + 150) = (2s + 450) collect like terms.
5s - 2s = 450 - 150
3s = 300 Divide both sides by 3
s = 300/3
s = 100
Therefore the sphere weighs 100 gram each.
1. 9 feet revelent to the surface
2. 19 points