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3 years ago

12

Find three ratios equivalent to the ratio described in the situation the ratio of cups of water to cups of milk in a recipe 1 to

5

1 answer:

Elis [28]3 years ago

6 0

10 + 10 = 21

dont ask howwwwww

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bija089 [108]

Answer:the answere is 3/40 I hope this help

Step-by-step explanation:

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3 years ago

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Firlakuza [10]

The chosen topic is not meant for use with this type of problem. Try the examples below.

$cot (3x),x=\frac{2\pi }{3}$

$cot ( \frac{x}{2}, x=\frac{\pi }{2}$

$cos (x), x = \frac{x}{2}$

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3 years ago

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aleksandrvk [35]

E. 9:12...............

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3 years ago

Can please send answers with step

lawyer [7]

Answer:

A. 14 Sq.cm

Step-by-step explanation:

The area of the circle is 56 cm Sq.

Half of it is 28 Sq.cm

If you combine the 2 triangles it will make an area of 7sq.cm

then the Curved shaded part is also 7sq.cm together of the shaded part will create a quarter of the whole figure

So

56/4 Sq.cm

= 14Sq.cm

Thank you!!

Mark me as brainliest :>>>

6 0

3 years ago

What are the roots of f(x) = x2 – 48? –48 and 48 –24 and 24 Negative 8 StartRoot 3 EndRoot and 8 StartRoot 3 EndRoot Negative 4

Ivanshal [37]

Answer:

$x=4\sqrt{3},\:x=-4\sqrt{3}$ are the roots.

Step-by-step explanation:

$x=4\sqrt{3},\:x=-4\sqrt{3}$

Considering the expression

$x^2\:-\:48$

Solving

$x^2-48=0$

$x^2-48+48=0+48$

$x^2=48$

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=\sqrt{48},\:x=-\sqrt{48}$

Solving

$x=\sqrt{48}$

= $\sqrt{2^4\cdot \:3}$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}$

= $\sqrt{3}\sqrt{2^4}$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^m}=a^{\frac{m}{n}}$

$\sqrt{2^4}=2^{\frac{4}{2}}=2^2$

$=2^2\sqrt{3}$

$=4\sqrt{3}$

So,

$x=4\sqrt{3}$

Similarly,

$x=-\sqrt{48}=-4\sqrt{3}$

Therefore, $x=4\sqrt{3},\:x=-4\sqrt{3}$ are the roots.

Keywords: roots, expression

Learn more about roots from brainly.com/question/3731376

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3 years ago

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