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MAXImum [283]
3 years ago
13

There are 375 books sold at Sid's Bookstore. The table below summarizes these books by genre. This info is presented in circle g

raph. Find the central angle measure for Self Help slice in graph. Mystery 99, romance 81, self help 90, cooking 57, biography 48.

Mathematics
1 answer:
loris [4]3 years ago
5 0
When you plot the data in a pie graph, it looks like that shown in the picture. A circle is formed when you draw a point and connect it from end to end forming a complete revolution. One revolution equals 360°. Therefore, each piece of pie for each type of book is a fraction of one revolution. The fraction can be determined by dividing the number for a specific type of book to the total number of books. Specifically, the fraction for the Self Help slice would be 90/375 which is equal to 0.24 or 24%. Then, 24% of 360 is 86.4. Therefore, the central angle formed by the Self Help slice is 86.4°.

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A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the
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Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1

The probability that at most 12 ties are too tight is P=1.

5 0
3 years ago
Who Washes? Erica and Aaron, who are siblings, have decided to use a lottery system to decide who will wash dishes every night.
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Given that Erica and AAron,are using lottery system to decide who will wash dishes every night.

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If the game is to be fair, then both should have equal chances of opportunity for washing.

i.e. Probability for Erica washing = Prob of Aaron washing

i.e. P(different chips) = P(same colour chips)

Say there are m red colours and n blue colours.

Both are drawing at the same time.

Hence Prob (getting same colour) = (mC2+nC2)/(m+n)C2

Probfor different colour = mC1+nC1/(m+n)C2

The two would be equal is mC2 +nC2 = m+n

This is possible if mC2 =m and nC2 = n.

Or m = 2+1 =3 and n =3

That for a fair game we must have both colours to be 3.


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