Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
Answer:
a) b) the standard deviation and the mean is affected by the conversion factor as well
c) the mean is displaced by b units
Step-by-step explanation:
for a new variable
Y=a*X , where a= constant (conversion factor= 1 kg/2.2 pounds)
then
p(y)= p(a*X) = p(X)
a) mean =μ=E(Y)= ∑ a*X*p(y) = a ∑ X*p(x) = a* E(X)
mean =μ=a*μₓ
b) σ² = ∑ (Y-μ)²* p(y) = ∑ (a*X-a μₓ)²* p(y) = a²*∑ (X-μₓ)²* p(x) = a²*σₓ²
then
standard deviation = σ= √σ²=√(a²*σₓ²) = a*σₓ
standard deviation = σ= a*σₓ
then the standard deviation and the mean is affected by the conversion factor as well
c) nevertheless for a displacement b
Y₂=X + b (b= constant= 50 gr)
p(Y₂)= p(X + b) = p(X)
then
mean =μ=∑ (X-b)*p(y)=∑ X*p(x)- b ∑ p(x) = E(X) -
mean =μ=μₓ - b
then the mean is displaced by b units
Answer:
h=3.5
Step-by-step explanation:
divide 28 by 8
hope I helped
Answer:
x=-13/9
Step-by-step explanation:
8/9=x+7/3
8/9-7/3=x
8/9-(3)7/9=x
8/9-21/9=x
-13/9=x
I hope this helped. If you have any questions, please feel free to ask them.
Answer:
Ok y= 2x + b
b referring to any number less than -2 and more than -2
so y=2x+4 can work
Step-by-step explanation:
parallel lines in slope-intercept form have the same slope, i.e. the same 'm' value or coefficient of <em>x</em><em> </em> but different interceptions
