We are given that there are a total of 78 students. If we set the following variables:
Then, the sum of all of these must be 78, that is:
Since there are 15 in chemistry and physics and 47 in chemistry, we may replace that into the equation and we get:
Simplifying:
Now we solve for P by subtracting 62 on both sides:
Therefore, there are 16 students in physics
Answer:
3 1/5 square units
Step-by-step explanation:
4 units * 4/5 shaded
4*4/5 = 16/5
Changing to a mixed number
5 goes into 16 3 times with 1 left over
3*5 = 15 16-15 = 1
3 1/5 square units
Answer: 0.26
Step-by-step explanation:
As per given , we have
P(green tail) = 0.36
P(red fins) = 0.59
P(both a green tail and red fins ) = 0.21
Now, P(Neither red fin nor green tail )= 1 - P(either red fin or green tail )
<em>[P(neither A nor B)= 1- P(either A or B)]</em>
= 1-(P(green tail) +P(red fins)+P(both a green tail and red fins ))
<em>[P(A or B)= P(A)+P(B)-P(A and B)]</em>
= 1- (0.36+0.59-0.21)
= 1-(0.74)
= 0.26
Hence, the probability that the selected fish will not have a red fin or a green tail = 0.26
Answer:
Step-by-step explanation:
So first you do y=z and1+2=3 so 6=y=-0 is your answer :)
Answer:
14>-9
Step-by-step explanation:
hope it work U_U enjoy tho