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gavmur [86]
3 years ago
14

Determine the theoretical probability of rolling a number larger than 3 on a standard 6-sided cube. 1/2, 1/6, 1/4, 1/3

Mathematics
2 answers:
nirvana33 [79]3 years ago
7 0
|\Omega|=6\\
|A|=3\\
P(A)=\dfrac{3}{6}=\dfrac{1}{2}
exis [7]3 years ago
7 0

Answer:

Option A is correct.

Step-by-step explanation:

Given: A 6-sided cube is rolled.

To find: Probability of getting a number greater than 3.

Total number of outcome when a 6-sided cube is rolled = 6

Favorable outcome = { 4 , 5  6 }

Number of favorable outcome = 3

Theoretical Probability is a probability based on reasoning written as a ratio of the number of favorable outcomes to the number of possible outcomes.

Probability=\frac{Number\:of\:favorable\:outcome}{Number\:of\:Total\:outcome}

Probability=\frac{3}{6}=\frac{1}{2}

Therefore, Option A is correct.

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Well you do 32 divided by 28% and get 8.96
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3 years ago
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What are the coordinates of the point obtained if the point A=(3,7) is rotated 180 degrees about the origin?
Yuliya22 [10]

Answer:

B. (-3, -7)

Step-by-step explanation:

Anytime you rotate a number 180° about the origin, the numbers in the coordinates become their opposites.

-3 is the opposite of 3 and -7 is the opposite of 7.

Therefore, your new coordinates are (-3, -7)

(x,y) becomes (-x,-y)

8 0
3 years ago
Points E, F, and D are on circle C, and angle G measures 60°. The measure of arc EF equals the measure of arc FD.
galben [10]

Answer:

∠EFD ≅ ∠EGD ⇒ A

Arc ED ≅ arc FD ⇒ C

m arc FD = 120° ⇒ E

Step-by-step explanation:

Let us revise some facts

  1. Equal chords subtended equal arcs
  2. The measure of an inscribed angle is one-half the measure of the central angle which subtended by the same arc
  3. The measure of a central angle is equal to the measure of its subtended arc
  4. If one angle of an isosceles triangle measure 60° then the triangle is equilateral
  5. The sum of the measures of the interior angles of any quadrilateral is 360°

In the quadrilateral  CDGE

∵ m∠G = 60°

∵ m∠GDC = m∠GEC = 90°

- By using the 5th rule above

∴ m∠G + m∠GDC + m∠DCE + m∠GEC = 360°

∴ 60 + 90 + m∠DCE + 90 = 360

∴ 240 + m∠DCE = 360

- Subtract 240 from both sides

∵ m∠DCE = 120°

In circle C

∵ ∠DCE is a central angle subtended by arc DE

∵ ∠DFE is an inscribed angle subtended by arc DE

- By using the 2nd rule above

∴ m∠DFE = \frac{1}{2} m∠∠DCE

∵ m∠DCE = 120°

∴ m∠DFE = \frac{1}{2} (120)

∴ m∠DFE = 60°

- That means ∠EFD ≅ ∠EGD because their measure is 60°

∴ ∠EFD ≅ ∠EGD

In Δ EFD

∵ EF = FD

∵ m∠DFE = 60°

- By using the 4th rule above

∴ Δ EFD is an equilateral triangle

∴ ED = FD = FE

In circle C

∵ Side ED subtended by arc ED

∵ Side FD subtended by FD

∵ Side ED ≅ side FD ⇒ proved

- By using the 1st rule above

∴ Arc ED ≅ arc FD

∵ m∠ECD = 120°

∵ ∠ECD is a central angle subtended by arc ED

- By using the 3rd rule above

∴ m∠ECD = m arc ED

∴ m of arc ED = 120°

∵ Arc ED ≅ arc FD

∴ m arc ED = m arc FD

∴ m arc FD = 120°

5 0
3 years ago
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If(√14/√7-2)-(√14/√7+2)=a√7+b√2 find the values of a and b where a and b are rational numbers​
seraphim [82]

Answer:

  • a = 4/3 and b = 0

============================

<h2>Given expression:</h2>

\dfrac{\sqrt{14} }{\sqrt{7}-2} -\dfrac{\sqrt{14} }{\sqrt{7}+2}

<h2>Simplify it in steps:</h2>

<h3>Step 1</h3>

Bring both fractions into common denominator:

\dfrac{\sqrt{14} (\sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} - \dfrac{\sqrt{14} (\sqrt{7}-2)}{(\sqrt{7}-2)(\sqrt{7}+2)}

<h3>Step 2</h3>

Simplify:

\dfrac{\sqrt{14} ((\sqrt{7}+2) - (\sqrt{7}-2))}{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{\sqrt{14} (\sqrt{7}+2 - \sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{4\sqrt{14} }{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{4\sqrt{14} }{(\sqrt{7})^2-2^2} =

\dfrac{4\sqrt{14} }{7-4} =

\dfrac{4}{3}  \sqrt{14} }

<h3>Step 3</h3>

Compare the result with given expression to get:

  • a = 4/3 and b = 0

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What is -1 = 5/8b + 3/8
andrew-mc [135]

Answer:

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decimal form - b = -2.2

Mixed number form - b = -2 1/5

4 0
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