8 - {x - (5 + x)}
= 8 - {x - 5 - x}
= 8 + 5
= 13
Answer:
{-1, 5} (two real solutions).
Step-by-step explanation:
On the left side we want x^2, not x?
We need to rewrite x? = 4x - 5 in standard form, that is, as a quadratic with x terms in decreasing powers of x:
x^2 - 4x + 5 = 0
This factors easily to (x - 5)(x + 1) = 0.
We let each factor equal zero (0) separately and solve for x:
{-1, 5} (two real solutions).
Answer:
<u>x<6/7</u>
Step-by-step explanation:
7x/3 < 2
7x < 6
<u>x < 6/7</u>
<u></u>
<h3><u>
If you need to ask any questions, please let me know.</u></h3>