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3 years ago

What is 99+1 x 4 worth 50 pts

2 answers:

6 0

Use PEMDAS to solve the problem.
PARENTHESIS
EXPONENTS
MULTIPLICATION
DIVISION
ADDITION
SUBTRACTION

In the problem $99 + 1 \times 4$ , there is only multiplication and addition.
According to PEMDAS, multiplication comes before addition. So you do that first.
$1 \times 4 = 4$
Now you add 4 and 99 to get your answer.
$99 + 4 = 103$
The answer is $\boxed{ 103 }$ .

However, it looks like in your question the 99+1 is separated from the 4. If the question was originally $(99 + 1) \times 4$ then we do the parenthesis first. 99 + 1 = 100. $100 \times 4 = 400$ .

So depending on your question,
$99+1\times4=\boxed{103}$
$(99+1)\times4=\boxed{400}$

stiks02 [169]3 years ago

6 0

99+1 times 4
so pemdas
there are no parenthasees or exponents so we move to multiplication
1 times 4=4
99+4
addition
99+4=103
the answe ris 103

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<u>Answer-</u>

a. Probability that three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

$\binom{19}{3} = \frac{19!}{3!16!} = 969$

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

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Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

$\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}$

$=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})$

$=(969)(45)(7)(5)(15)=22892625$

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$\binom{52}{9}=\frac{52!}{9!43!} =3679075400$

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

$\frac{22892625}{3679075400} = 0.006$

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