What is the area of a triangle whose vertices are P(−1, 4), Q(3, 2), and R(3, −4)?

1 answer:

sp2606 [1]2 years ago

7 0

What kind of triangle is it?

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Kruka [31]

Answer:

Step-by-step explanation:

to evaluate substitute x = 0 and x = 1 into f(x)

note that $a^{0}$ = 1

f(0) = 45 × $(1/3)^{0}$ = 45 × 1 = 45

f(1) = 45 × $(1/3)^{1}$ = 45 × $\frac{1}{3}$ = 15

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Furkat [3]

AB=√{(6+3)²+(6-2)^2}=√(81+16)=√(97)

BC=√((7-6)²+(-1-6)²)=√(50)=5√2

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Brrunno [24]

Answer:

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Step-by-step explanation:

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