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3 years ago

How do the X- and Y-coordinates change when a figure is translated right a units and down b units?

2 answers:

Natasha2012 [34]3 years ago

4 0

Hey there,

The x and y coordinates change as a shape or figure moves up and down, left or right. As something goes up numbers get bigger and down the numbers get smaller.

Hope I helped :)

Elodia [21]3 years ago

3 0

Translating right means to move horizontal on the x axis changing the x coordinate.
same for y coordinate but going up means moving vertically

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The regression equation y=0.5x+1.3 approximates the number of hours it takes to arrange a dinner event, y, given the number of p

Sphinxa [80]

It would be C.

For example, say 1 person comes. This would be x=1. Plugging this in gives you,

y=0.5 + 1.3

This shows that C is true since x is always going to be multiplied by 0.5.

1.3 would be the base amount of time it takes to arrange since if it the y-intercept.

5 0

3 years ago

Round 83,461 to the nearest thousand.

ch4aika [34]

Answer:

See below.

Step-by-step explanation:

83,461

This is the thousand place.

5 and above is rounded up, 4 and below is rounded down.

83,000 is the answer.

-hope it helps

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2 years ago

PLEASE HELP GIVING BRAINLIEST 25 POINTS!

tatiyna

Answer:

nearest tenth= 5.4

Step-by-step explanation:

55 ÷ 10.1= 5.44554455446.

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2 years ago

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The length of a city’s bus routes are normally distributed with a mean of 14.5 mi and a standard deviation of 3.2 mi.

jeka57 [31]

Thank you for posting your question here at brainly. Please see below answer:

a) What percentage of city bus routes are less than 15 mi?
56.20820167 ≈ 56.2%

b)What percentage of city bus routes are greater than 20 mi?
4.282995170 ≈ 4.3 %

c) What percentage of city bus routes are less than 10 mi?
<span>7.98 ≈ 7.98 %</span>

3 0

3 years ago

Simplify<br> 7^2x^-3y/49x^-3y^-2

olya-2409 [2.1K]

$\frac{7^2x^{-3}}{49x^{-3} y^{-2}} \\ \\ \frac{49x^{-3}y}{49x^{-3}y^{-2}} \\ \\ \frac{49x^{-3}y}{49x^{-3} \times \frac{1}{y^2} } \\ \\ \frac{49x^{-3}y}{ \frac{49x^{-3}}{y^2} } \\ \\ 49x^{-3} y \times \frac{y^2}{49x^{-3}} \\ \\ \frac{x^{-3}}{x^{-3}} yy^2 \\ \\ 1 \times yy^2 \\ \\ yy^2 \\ \\ y^3 \\ \\$

The answer is: y^3.

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3 years ago

Read 2 more answers