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Charra [1.4K]
3 years ago
15

Help me please i’m failing lol

Mathematics
2 answers:
Effectus [21]3 years ago
7 0
16) K= 176
18) X= 12
20) M= - 52
22) X = -13
24) A= -90
Hope that helps :)
nalin [4]3 years ago
6 0

16) k=176 hope you get to a point were your not failing

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sergejj [24]

Answer:1/8, 3/6, 3/4


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3 years ago
There are 24 students on the field trip. How many parents will be needed to put them into groups of 3?
Vika [28.1K]

24 students / 3 groups = 8

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6 0
3 years ago
Differentiate x^2 e^x logx
zimovet [89]

Product rule:

\dfrac{\mathrm d}{\mathrm dx}(x^2e^x\log x)

=\dfrac{\mathrm d(x^2)}{\mathrm dx}e^x\log x+x^2\dfrac{\mathrm d(e^x)}{\mathrm dx}\log x+x^2e^x\dfrac{\mathrm d(\log x)}{\mathrm dx}

Power rule:

\dfrac{\mathrm d(x^2)}{\mathrm dx}=2x

The exponential function is its own derivative:

\dfrac{\mathrm d(e^x)}{\mathrm dx}=e^x

Assuming the base of \log x is e, its derivative is

\dfrac{\mathrm d(\log x)}{\mathrm dx}=\dfrac1x

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y=\log_bx\implies x=b^y=e^{y\ln b}\implies1=e^{y\ln b}\ln b\dfrac{\mathrm dy}{\mathrm dx}

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{e^{-y\ln b}}{\ln b}=\dfrac1{b^y\ln b}

\implies\dfrac{\mathrm d(\log_bx)}{\mathrm dx}=\dfrac1{x\ln b}

So we end up with

2xe^x\log x+x^2e^x\log x+\dfrac{x^2e^x}x

=xe^x(2\log x+x\log x+1)

8 0
3 years ago
Choose the correct description of the graph of the compound inequality x − 1 less than or equal to 9 or 2x greater than or equal
DerKrebs [107]
X - 1 < = 9         or         2x > = 24
x < = 9 + 1                    x > = 24/2
x < = 10                        x > = 12

closed circle on 10, shaded to the left
closed circle on 12, shaded to the right

________10_______12__________
       <====X                 X======>
the X represents closed circles
8 0
3 years ago
W = A/L<br> (solve for A)<br> A = W +L<br> A = W-L<br> A = W/L<br> A = LW
kipiarov [429]
A=wl, so the answer is A :)
6 0
3 years ago
Read 2 more answers
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