Answer:
Perpendicular with respects to what?
You can't find it with only a point, you also need a slope to know which line is which.
There are an infinite number of lines that go through any point. Each has a slope, without slopes, we cant solve such a question.
It's line asking, how old is Jane's dog?
Who knows man? There's like thousands of Janes, which one is the one?
Multiply, because the total price is ten percent more than the original: $75 x 1.1 = <span>$82.5</span>
The 4 is in the ten thousands place, and the thousands place
hope this helps
Answer:
(r o g)(2) = 4
(q o r)(2) = 14
Step-by-step explanation:
Given


Solving (a): (r o q)(2)
In function:
(r o g)(x) = r(g(x))
So, first we calculate g(2)




Next, we calculate r(g(2))
Substitute 9 for g(2)in r(g(2))
r(q(2)) = r(9)
This gives:


{

Hence:
(r o g)(2) = 4
Solving (b): (q o r)(2)
So, first we calculate r(2)




Next, we calculate g(r(2))
Substitute 3 for r(2)in g(r(2))
g(r(2)) = g(3)




Hence:
(q o r)(2) = 14