1/2in = 16 mi
2 3/4 in without whole numbers [(denominator ×whole) + numerator] / denominator
4×2 = 8 +3 = 11/4
Find common denominator for 1/2 and 11/4 (common D Is 4)
Multiply 1/2 by 2/2
2/4 in = 16 mi divide this by 2
2/4 ×1/2 = 1/4
16 /2 = 8
1/4 = 8
1/4 goes into 11/4 11 times
Multiply 8 times 11
88 miles (D)
End zone to end zone is = length so his scale is 6 in and in real life it is 360 ft
To find scale divide 360 by 6
1in = 60 ft (B)
160 ft wide
(divide 160 by 60 ft ) fraction
160/60 is a fraction now simplify
16/6
Common factors of both numbers is 2
Simplify by 2
8/3
Make into whole number fraction
3 goes into 8 two times (2×3=6)(2 becomes whole number) while there's is 2 left over( 8 -6=2) (becoming the numerator)
2 2/3 in (B)
120 ft long
80 ft wide
24 in is scale of "long"
Divide 120 by 24
120÷24=5
So 5in in scale equals 1ft in real life
To find width in scale divide 80 by 5
80/5= 16in (A)
If you have any trouble understanding feel free to let me know I will try to explain as best as I can :)
F(t)=1.4^t
<span>a)a=1, b=0.4 </span>
<span>b)a=1.4, b=0<<<< </span>
<span>c)a=1.4, b=t </span>
<span>d)a=1, b=1.4
Hope this helped!!</span>
Answer:
Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values. Tap for more steps.
Step-by-step explanation:
Answer:
x=103/265 y=18/53
Step-by-step explanation:
5x -9y=1-----------(i)
-7x+2y=-5-----------(ii)
Multiplying eq 1 with 7 gives
35x-63y=7---------eq(iii)
Multiplying eq 2 with 5 gives
-35x+10y=-25--------eq(iv)
adding eq 3 qnd eq 4
35x-63y-35x+10y=7-25
-53y=-18
y=18/53--------eq5
Putting the value of y from eq 5 in eq 1
5x-9(18/53)=-5
5x- 162/53=-5
5x=-5 +162/53
5x= -265+162/53
5x=103/53
x=103/265
Answer:
332
Step-by-step explanation:
To find how many seats there were, multiply the number of rows with the number of seats in each row:
15 (24) = 360
From these total seats, there are 28 empty seats, meaning:
360 - 28 = 332
There were 332 people.
