Answer:
The number of pounds of cashew is 11
Step-by-step explanation:
Let P represent the peanut
Let C represent the cashew nut.
From question, we were told that Elijah brought a total of 16 pounds of peanuts and cashew nuts. This can be written as:
P + C = 16 (1)
The total cost = $49.50
Cost per peanut = $2.75
Cost per cashew = $3.25
The above can be represented as:
49.50 = 2.75P + 3.25C. (2)
From equation 1,
P + C = 16
P = 16 — C
Substitute the value of P into equation 2:
49.50 = 2.75P + 3.25C.
49.50 = 2.75(16 — C) + 3.25C
49.50 = 44 — 2.75C + 3.25C
49.50 = 44 + 0.5C
Collect like terms
49.50 — 44 = 0.5C
5.5 = 0.5C
Divide both side by 0.5
C = 5.5/0.5
C = 11
Therefore, the number of pounds of cashew is 11
Answer:
61 m^3
Step-by-step explanation:
The difference in volume is (5 m)^3 - (4 m)^3, or (125 - 64) m^3, or
61 m^3
Answer:
Step-by-step explanation:
Hi there!
Distribute 2/3 and 5 into the parentheses:
Combine like terms:
I hope this helps!
Answer:
C. with 3000 successes of 5000 cases sample
Step-by-step explanation:
Given that we need to test if the proportion of success is greater than 0.5.
From the given options, we can see that they all have the same proportion which equals to;
Proportion p = 30/50 = 600/1000 = 0.6
p = 0.6
But we can notice that the number of samples in each case is different.
Test statistic z score can be calculated with the formula below;
z = (p^−po)/√{po(1−po)/n}
Where,
z= Test statistics
n = Sample size
po = Null hypothesized value
p^ = Observed proportion
Since all other variables are the same for all the cases except sample size, from the formula for the test statistics we can see that the higher the value of sample size (n) the higher the test statistics (z) and the highest z gives the strongest evidence for the alternative hypothesis. So the option with the highest sample size gives the strongest evidence for the alternative hypothesis.
Therefore, option C with sample size 5000 and proportion 0.6 has the highest sample size. Hence, option C gives the strongest evidence for the alternative hypothesis
