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2 years ago

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Net income is equal to the total revenue from selling an item minus the cost of producing the item. Determine the net income if

the revenue from a business is $400,000 and the cost is $156,800. Use 4072-01-01-03-00_files/i0330000.jpg where I = net income, R = revenue, C = cost

1 answer:

Travka [436]2 years ago

3 0

C-Cost because it the most reasonableness one

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A flower pot has a radius of 10 inches. Evelyn wants to tie a ribbon around the pot. How long does the ribbon have to be in orde

mariarad [96]

Answer:68.5

Step-by-step explanation:

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2 years ago

AB has a vértices at (-5,1) and (-3,7). After a transformation, the image had endpoints at (3,-1) and (5,5). Describe the transf

Scrat [10]

That looks like a translation; let's check. We have

A(-5,1), B(-3,7), A'(3,-1), B'(5,5)

If it's a translation by T(x,y) we'd have

A' = A + T

B' = B + T

so

T = A' - A = (3,-1) - (-5,1) = (8,-2)

and also

T = B' - B = (5, 5) - (-3, 7) = (8,-2)

They're the same so we've verified this transformation is a translation by (8,-2), eight right, two down.

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2 years ago

Read 2 more answers

What is the decimal conversion of 8 39/40 and does the decimal repeat or terminate?

alukav5142 [94]

The decimal conversion to 8 39/40 is 8.975 and the decimal terminates.

3 0

3 years ago

The head librarian at the Library of Congress has asked her assistant for an interval estimate of the mean number of books check

Verdich [7]

Answer:

$n=(\frac{1.960(150)}{90})^2 =10.67 \approx 11$

So the answer for this case would be n=11 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma =150$ represent the population standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The confidence interval for this case is given by: (740, 920)

We can find the estimate for the mean and we got:

$\bar X = \frac{740+920}{2} = 830$

and the margin of error is given by :

$ME = \frac{920-740}{2}= 90$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =90 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(150)}{90})^2 =10.67 \approx 11$

So the answer for this case would be n=11 rounded up to the nearest integer

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2 years ago

Is 2/10 smaller than 19/100?

s344n2d4d5 [400]

Answer:

Step-by-step explanation:

no cause 2/10 is the same as 20/100

8 0

2 years ago