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3 years ago

Using common denominator, what is an equivalent fraction for 1/3?

Mathematics

2 answers:

allsm [11]3 years ago

5 0

Answer:

2/6

Step-by-step explanation:

We can for example multiply both numerator and denominator by 2

(1*2)/(3*2) = 2/6

Fed [463]3 years ago

3 0

Answer: An example of an equivalent fraction for 1/3 is 3/9.

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For one binomial experiment, n1 = 75 binomial trials produced r1 = 30 successes. For a second independent binomial experiment, n

Masja [62]

The correct answer to your question would be B because it’s computea with the corresponding sample that distributes the value. welcome.

7 0

2 years ago

solve, showing all work. state if there is one solution, no solution, or infinite solutions -3(k+2)=-3k+7. please help i need an

WARRIOR [948]

Answer:

-6=7 NO SOLUTION

Step-by-step explanation:

First, distribute the -3 to the (k +2)

Your equation becomes, -3k-6=-3k+7

Add 3k to both sides to have the variables be on the same side

Your equation becomes, -6=7

Since that isn’t true, it’s a no solution

I hope this helps!

8 0

3 years ago

Mark's school is selling tickets to the annual dance competition. On the first day of ticket sales the school sold 4 senior tick

erica [24]

The cost of each senior ticket is $ 5 and cost of each child ticket is $ 12

Solution:

Let "a" be the price of each senior ticket

Let "b" be the price of each child ticket

On the first day of ticket sales the school sold 4 senior tickets and 4 child tickets for a to total of 68

Thus a equation is framed as:

4 senior tickets x price of each senior ticket + 4 child tickets x price of each child ticket = 68

$4 \times a + 4 \times b = 68$

4a + 4b = 68 ---------- eqn 1

The school took in 120 on the second day by selling 12 senior tickets and 5 child tickets

Similarly, we frame a equation as:

$12 \times a + 5 \times b = 120$

12a + 5b = 120 ---------- eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 1 by 3

12a + 12b = 204 -------- eqn 3

Subtract eqn 2 from eqn 3

12a + 12b = 204

12a + 5b = 120

( - ) --------------

7b = 84

b = 12

Substitute b = 12 in eqn 1

4a + 4(12) = 68

4a + 48 = 68

4a = 20

a = 5

Thus cost of each senior ticket is $ 5 and cost of each child ticket is $ 12

4 0

3 years ago

Two less than 1/4 the cube of x is y =

enyata [817]

Cube of x is x^3, according to question

Y= 1/4 x ^3 -2

8 0

3 years ago

What is the product?(4y − 3)(2y2 + 3y − 5)8y3 + 3y + 158y3 − 23y + 158y3 − 6y2 − 17y + 158y3 + 6y2 − 29y + 15

motikmotik

We need to find the product of :

$\mleft(4y-3\mright)\mleft(2y2+3y-5\mright)$

So, the result as following:

$\begin{gathered} \mleft(4y-3\mright)\mleft(2y^2+3y-5\mright) \\ =4y\cdot(2y^2+3y-5)-3\cdot(2y^2+3y-5) \\ =8y^3+12y^2-20y-(6y^2+9y-15) \\ =8y^3+12y^2-20y-6y^2-9y+15 \\ \\ =8y^3+6y^2-29y+15 \end{gathered}$

So, the answer is the option 4. 8y3 + 6y2 − 29y + 15

5 0

1 year ago