import java.util.Scanner;
public class JavaApplication40 {
public static void printGPA(Scanner scan){
System.out.println("Enter a student name:");
String name = scan.nextLine();
System.out.println("Enter the number of courses:");
int courses = scan.nextInt();
double total = 0;
for (int i = 1; i <= courses; i++){
System.out.println("Course "+i+" Grade:");
double grade = scan.nextDouble();
total += grade;
}
System.out.println(name+"'s grade is "+(total/courses));
}
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
printGPA(scan);
}
}
I hope this helps!
The number of unique processes that are created is in the original process, you get the PID of the child process. In the child process, you get 0.
<h3>What is a Code Segment?</h3>
This refers to the portion of an object file that is in the virtual space of a computer that contains executable instructions.
Hence, we can note that since PID >= 0, then there would be the creation of two identical processes in which the original process returns the PID of the child process, and the output in the child process would be zero.
If we make use of a canonical tag,
p = fork();\\if (0 == p)
{
// We're the child process
}
else if (p > 0)
{
// We're the parent process
}
else
{
// We're the parent process, but the child couldn't be created
}
Read more about code segments here:
brainly.com/question/25781514
#SPJ1
