Given:
Number of black marbles = 6
Number of white marbles = 6
Let's determine the least number of marbles that can be chosen to be certain that you have chosen two marble of the same color.
To find the least number of marble to be chosen to be cartain you have chosen two marbles of the same color, we have:
Total number of marbles = 6 + 6 = 12
Number of marbles to ensure at least one black marble is chosen = 6 + 1 = 7
Number of marbles to ensure at least one white marble is chosen = 1 + 6 = 7
Therefore, the least number of marbles that you must choose, without looking , to be certain that you have chosen two marbles of the same color is 7.
ANSWER:
7
Answer:
4
or 4.75
Step-by-step explanation:
first we're going to convert the number into improper fractions.
7
=
and 2
= 
For subtracting it is suitable to adjust both fractions to an equal denominator, so we're going to multiply
x2, it'll equal the same number.
So now we have
-
, 30-11= 19.
simplified is, 4
.
As you can see I also added 4.75 as an answer, that's if the answer must be a decimal.
I hope this helps you!
Let x = Barbie's number
1/3 x -20 = 72
1/3 x = 92
x = 92*3=276
<span>Simplifying
7p + 2 = 5p + 8
Reorder the terms:
2 + 7p = 5p + 8
Reorder the terms:
2 + 7p = 8 + 5p
Solving
2 + 7p = 8 + 5p
Solving for variable 'p'.
Move all terms containing p to the left, all other terms to the right.
Add '-5p' to each side of the equation.
2 + 7p + -5p = 8 + 5p + -5p</span>
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