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alexgriva [62]
3 years ago
8

10 points if you solve this one problem.

Mathematics
1 answer:
zalisa [80]3 years ago
7 0

Answer:

150

Step-by-step explanation:

The exterior angle is equal to the sum of the opposite interior angles

<1 + <2 = <3

3x+11 + 3x+19 = 7x+10

Combine like terms

6x+30 = 7x+10

Subtract 6x from each side

6x -6x+30 = 7x-6x+10

30 = x+10

Subtract 10 from each side

30-10 = x+10-10

20 =x

We need to find angle 3

<3 = 7x+10

    = 7(20)+10

    = 140+10

    = 150

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Answer:

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Step-by-step explanation:

Write 10% as a decimal then divide 3 by 0.1 (10% as a decimal)

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a fruit delivers its fruit in two types of boxes: large and small. a delivery of 3 large boxes and 5 small boxes has a total wei
Masteriza [31]

Answer:

The weight of a small box  = 13.5 kg

The weight of 1 large box = 18.5 kg

Step-by-step explanation:

Let us assume the weight of a small box = m kg

And the weight of 1 large box  = n kg

Now, the weight of 5 small box = 5 x (weight of 1 small box) =  5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) =  3 n

Here,   3 large boxes +  5 small boxes =  of 123 kilograms

⇒ 5  m + 3 n = 123   .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) =  2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) =  12 n

Here,   12 large boxes +  2 small boxes =  249 kilograms

⇒ 2 m+ 12 n = 249   .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5  m + 3 n = 123     x (2)

2 m+ 12 n = 249     x (-5)

we get the new set of equitation as:

10 m + 6 n = 246

- 10 m - 60 n =  -1245

Adding both equation, we get

-54 n = 999

or, n = 18.5

Now, 5  m + 3 n = 123

So, 5 m = 123  -3 (18.5)  = 123 - 55.5 =  67.5

⇒  m = 13.5

Hence,  the weight of a small box = m kg = 13.5 kg

And the weight of 1 large box = n kg  = 18.5 kg

8 0
3 years ago
Helpp please!!!
zavuch27 [327]

Answer:

  h, j2, f, g, j1, i, k, l (ell)

Step-by-step explanation:

The horizontal asymptote is the constant term of the quotient of the numerator and denominator functions. Generally, it it is the coefficient of the ratio of the highest-degree terms (when they have the same degree). It is zero if the denominator has a higher degree (as for function f(x)).

We note there are two functions named j(x). The one appearing second from the top of the list we'll call j1(x); the one third from the bottom we'll call j2(x).

The horizontal asymptotes are ...

  • h(x): 16x/(-4x) = -4
  • j1(x): 2x^2/x^2 = 2
  • i(x): 3x/x = 3
  • l(x): 15x/(2x) = 7.5
  • g(x): x^2/x^2 = 1
  • j2(x): 3x^2/-x^2 = -3
  • f(x): 0x^2/(12x^2) = 0
  • k(x): 5x^2/x^2 = 5

So, the ordering least-to-greatest is ...

  h (-4), j2 (-3), f (0), g (1), j1 (2), i (3), k (5), l (7.5)

6 0
3 years ago
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