Ask question

Ask question

All categories

3 years ago

8

10 points if you solve this one problem.

1 answer:

zalisa [80]3 years ago

7 0

Answer:

150

Step-by-step explanation:

The exterior angle is equal to the sum of the opposite interior angles

<1 + <2 = <3

3x+11 + 3x+19 = 7x+10

Combine like terms

6x+30 = 7x+10

Subtract 6x from each side

6x -6x+30 = 7x-6x+10

30 = x+10

Subtract 10 from each side

30-10 = x+10-10

20 =x

We need to find angle 3

<3 = 7x+10

= 7(20)+10

= 140+10

= 150

You might be interested in

(12) Check all that apply. Inequalities

MrRa [10]

The circle is open i think is the right answer i hope i got it right if not im very sorry :(

6 0

3 years ago

A gym teacher has 250 to spend on volleyball, she buys for volleyball nets that cost $28 volleyballs are $7 each.how many volley

MaRussiya [10]

The gym teacher has $250 to spend on volleyball equipment. She buys 4 volleyball nets for $28 each. Volleyballs cost $7 each. How many volley balls can she buy

Answer:

she can buy maximum of 19 balls.

Step-by-step explanation:

Let the number of volleyballs be x

we know that

$\text{(The cost of each volleyball net} \times \text{number of volleyball net)}+\text{(the cost of each volleyball} \times \text{number of volleyballs)}\leq \ 250$

so substituting the values,

$28(4) + 7x \leq 250$

$112 + 7x \leq 250$

$7x \leq 250 - 112$

$7x \leq 138$

$x \leq \frac{138}{7}$

$x \leq 19.7$

3 0

3 years ago

2/8 is what as a decimal

Lilit [14]

2/8 is .25 as a decimal .

8 0

3 years ago

Write the equation of the parabola that has its x-intercepts at (1+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B5%7D" id="TexForm

VladimirAG [237]

Answer:

$y=2x^2-4x-8$

Step-by-step explanation:

<u>Factored form of a parabola</u>

$y=a(x-p)(x-q)$

where:

p and q are the x-intercepts.
a is some constant.

Given x-intercepts:

(1+√5, 0)
(1-√5, 0)

Therefore:

$\implies y=a(x-(1+\sqrt{5}))(x-(1-\sqrt{5}))$

$\implies y=a(x-1-\sqrt{5})(x-1+\sqrt{5})$

To find a, substitute the given point (4, 8) into the equation and solve for a:

$\implies a(4-1-\sqrt{5})(4-1+\sqrt{5})=8$

$\implies a(3-\sqrt{5})(3+\sqrt{5})=8$

$\implies4a=8$

$\implies a=2$

Therefore, the equation of the parabola in factored form is:

$\implies y=2(x-1-\sqrt{5})(x-1+\sqrt{5})$

Expand so that the equation is in standard form:

$\implies y=2(x^2-x+\sqrt{5}x-x+1-\sqrt{5}-\sqrt{5}x+\sqrt{5}-5)$

$\implies y=2(x^2-x-x+\sqrt{5}x-\sqrt{5}x+\sqrt{5}-\sqrt{5}+1-5)$

$\implies y=2(x^2-2x-4)$

$\implies y=2x^2-4x-8$

6 0

2 years ago

Find the range, median, upper extreme, lower extreme, and interquartile range of the following data: 85, 85, 2, 1, 204, 123, 24,

Korvikt [17]

Do you are do me are you di I number 285g72

4 0

2 years ago