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3 years ago

Joelle is working on a school report in a word processor. She wants to place an oversized image which is

Mathematics

1 answer:

Inessa [10]3 years ago

8 0

Answer:

-4.46cm

Step-by-step explanation:

Width of the oversized image = 30.51cm

Width of the word processor page = 21.59cm

First step is subtract the width of the word processor page from the width of the oversized image

30.51cm - 21.59cm

= 8.92cm is the space left

Since we have two sides, horizontal positions to the left most side and horizontal positions to the right of the left most edge of the page

The next step is we divide 8.92 by 2

= 8.92cm ÷ 2

= 4.46cm

We have been told that in the question that the horizontal positions to the right of the leftmost edge of the page are positive.

Automatically, horizontal position for the left edge of the image which Joelle should use to center the image would the negative.

Therefore, horizontal position for the left edge of the image which Joelle should use to center the image = -4.46cm

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