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soldier1979 [14.2K]
3 years ago
9

Roscoe rides his bike at least 10 miles but not more than 30 miles. He rides at an average rate of 10.5 miles per hour. The amou

nt of time it takes for Roscoe to ride his bike m miles is represented by a function.
  t(m)= m 10.5
What is the practical domain of the function?
All integers from 0 to 50, inclusive
All integers from 10 to 50, inclusive
All real numbers
All multiples of 20 between 0 and 1000, Inclusive

Please explain how you got your answer too, thank you!
Mathematics
1 answer:
zheka24 [161]3 years ago
3 0

Actually, the domain is the possible set of input values of a function that will make the function fit the specific criteria. In this case, the input value is m, where m is the number of miles that is travelled. The criteria is to travel at least 10 miles but not more than 30 miles, therefore the domain should be:

 

All real numbers from 10 to 30, inclusive

 

(should be real numbers not integer since any fractional number is included in the domain)

 

I cannot figure out why the choices are far from the answer.

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Answer:

B

Step-by-step explanation:

P(AUB)=P(A)+P(B)-P(A∩B)

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<img src="https://tex.z-dn.net/?f=9%5C%3A%20%20%5C%3A%20%20%5Cfrac%7B%20%5Csin%28%20%5Ctheta%29%20%7D%7B1%20%2B%20%20%5Ccos%28%2
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Option (b) is your correct answer.

Step-by-step explanation:

\large\underline{\sf{Solution-}}

Given Trigonometric expression is

\rm :\longmapsto\:\dfrac{sin\theta }{1 + cos\theta }

So, on rationalizing the denominator, we get

\rm \:  =  \: \dfrac{sin\theta }{1 + cos\theta }  \times \dfrac{1 - cos\theta }{1 - cos\theta }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) =  {x}^{2} -  {y}^{2} \: }}}

So, using this, we get

\rm \:  =  \: \dfrac{sin\theta (1  -  cos\theta )}{1 -  {cos}^{2}\theta  }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {sin}^{2}x +  {cos}^{2}x = 1}}}

So, using this identity, we get

\rm \:  =  \: \dfrac{sin\theta (1 -  cos\theta )}{{sin}^{2}\theta  }

\rm \:  =  \: \dfrac{1 - cos\theta }{sin\theta }

<u>Hence, </u>

\\ \red{\rm\implies \:\boxed{\tt{ \rm \:\dfrac{sin\theta }{1 + cos\theta }   =  \: \dfrac{1 - cos\theta }{sin\theta } }}} \\

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