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3 years ago

7oz is equal to how many lbs round it to the nearest tenth

1 answer:

7 0

There are 16 ounces in one pound. So we do 7 divided by 16 to get our answer.

7 / 16 = 0.4375 ≈ 0.4 lbs

7 oz is approximately 0.4 lbs.

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Solve equation x(x-2) (x- 1) =0

ivanzaharov [21]

Answer:

Step-by-step explanation:

<em>The product is 0 if one of the factors is 0.</em>

$x(x - 2)(x - 1) = 0\iff x=0\ \vee\ x-2=0\ \vee\ x-1=0\\\\(1)\ x=0\\\\(2)\ x-2=0\qquad\text{add 2 to both sides}\\.\qquad x=2\\\\(3)\ x-1=0\qquad\text{add 1 to both sides}\\.\qquad x=1$

6 0

3 years ago

Lem is playing a board game and needs to roll two dice and get a six on both die in order to win the game. What is the probabili

tangare [24]

The probability of getting a 6 on one dice is 1/6

The probability of getting a 6 on both dice would be 1/6 x 1/6 = 1/36

Answer: 1/36

3 0

3 years ago

Which values of x would make a polynomial equal to zero if the factors of the polynomial were (x-5) and (x-6)

meriva

x-5= 0

move -5 to the other side

sign changes from -5 to +5

x-5+5= 0+5

x= 5

x-6= 0

x-6+6= 0+6

x= 6

Answer: B. 5 and 6

5 0

3 years ago

Read 2 more answers

If the trapezoid on the grid below is translated by using the rule (x,y)-> (x-4,y-3) what will be the coordinates of B’?

vesna_86 [32]

Answer:

B'(3, 5)

Step-by-step explanation:

Rule for the translation of a point (x, y) by 'h' units left and 'k' units upwards,

(x, y) → (x - h, y + k)

If h = 4 and k = 3,

$(x, y)\rightarrow(x-4,y+3)$

Following this rule coordinates of the image point of B will be,

B(7, 2) → B'(7 - 4, 2 + 3)

→ B'(3, 5)

Therefore, coordinates of the image point B' will be,

B'(3, 5)

6 0

3 years ago

Problem 5. Buses arrive at 116th and Broadway at the times of a Poisson arrival process with intensity λ arrivals per hour. Thes

Shtirlitz [24]

Answer:

Step-by-step explanation:

The problem states that there are only two types of busses - M104 and M6 with probable occurence of 0.6 and 0.4 respectively.

If the average number of busses arriving per hour is λ, the average number of M6 busses per hour is 0.4λ

Now consider a set of 3 M6 busses as an event. The average number of such events per hour will be

μ = 0.4λ / 3

The expected number of hours for the event "THIRD M6 arrives", let's say X is

E[X] = 1 / μ ( exponential distribution) = 3 / 0.4λ

= 7.5 / λ

The variance of event X is =

$Var[x] = \frac{1}{U^2} = \frac{56.25}{\lambda ^2}$

6 0

3 years ago