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vlabodo [156]
3 years ago
9

Hannah has $2 worth of dimes and quarters. She has a total of 17 dimes and quarters altogether. By following the steps below, de

termine the number of dimes, x,x, and the number of quarters, y,y, that Hannah has.
Mathematics
1 answer:
sineoko [7]3 years ago
4 0

Answer:

2 quarters and 15 dimes

Step-by-step explanation:

15 dimes = $1.50

2 quarters = $0.50

$1.50+$0.50=$2.00

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A 4-column table with 4 rows titled Population Data. Column 1 has entries 4, 5, 9, 15. Column 2 has entries 8, 2, 20, 1. Column
zheka24 [161]

Answer: Row 3

Row 2

6 and 10

Step-by-step explanation: C B A

5 0
2 years ago
A conductor needs 5 cellists and 5 violinists to play at a diplomatic event. to do this, he ranks the orchestra's 10 cellists an
DaniilM [7]
Ranking is very critical in this problem. Therefore, the most applicable mathematical theory is permutations.

Ranking possible for the cellists:
Needed cellists = 5
Total available cellists = 10
Possible number of rankings = 10P5 = 10!/(10-5)! = 30240

Ranking possible for the violinists:
Needed violinists = 5
Total available = 16
Possible number of rankings = 16P5 = 16!/(16-5)! = 524160

Therefore,
Ratio of rankings (cellists to violinists) = 30240/524160 = 3/52
3 0
3 years ago
An engineer is designing a large steel pad to be installed on the deck of an aircraft carrier. Its total volume will be 18 yd^3.
Shtirlitz [24]

Answer:

The cost of the material for the full-sized pad is;

d) 222,750.00

Step-by-step explanation:

The parameters of the steel pad and the scale model are;

The volume of the deck = 18 yd³

The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick

The weight of the sample, m₂ = 75 lbs

The cost of the steel, P = $55/lb

The dimensions of the sample in yards are;

6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0.\overline 1 yards

The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0.\overline 1 yd. =  (1/3) yd.³

The density of the sample material, ρ = m₂/V₂

∴ The density of the sample material, ρ = 75 lbs/((1/3)yd.³) = 225 lbs/yd³

Therefore, the density of the material of the pad, ρ = 225 lbs/yd³

The mass of the steel  pad, m₁ = ρ × V₁

∴ The mass of the steel  pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs

The cost of the material for the full-sized steel pad, C = m₁ × P

∴ C = 4,050 lbs × $55/lb = $222,750

6 0
3 years ago
How do you use repeat subtraction to determine 4 divided by 2/5.
kolezko [41]
2×2 because 4 so do 2×2 then get 4 and you remander will be 1
3 0
3 years ago
What is the median of the following values? 45, 32, 21, 12, 9, 33, 69, 71, 28, 5?
iVinArrow [24]
5, 9, 12, 21, 28, 32, 33, 45, 69, 71,

28+32/2 = 30
The median is 30
8 0
3 years ago
Read 2 more answers
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