Width of rectangle = x
Length =3x+7
Perimeter of rectangle = 158cm
2(l+w)=158
2(3x+7+x)=158
2(4x+7)=158
8x+14=158
8x=158-14
x=144/8
x=18
Therefore the width of the rectangle is 18cm
Length=3x+18+7
54+7=61cm
Area=lxw
=61x18
=1098^2
Answer:
the length is 10
Step-by-step explanation:
√(1 - 9)2 + (12 - 18)2 =
√(-8)2 + (-6)2 = √64 + 36 =
√100= 10
48 marks. Because 80/10 is 8. 8x6 =48
A trapezoid is a polygon of four sides with two parallel sides.
The area of trapezoid is the half sum of the lengths of the paralled sides times the height which is the distance between the parallel sides.
Call b1 and b2 the lengths of the two parallel sides and H the heigth, the formula is [1/2](b1 + b2) H.
We know b1 = 12cm, b2 = 12cm + 2 cm, and the area = 39 cm^2, then we can find H:
39 = [1/2](12 + 14)*H
39 = (13/2)H => H = 2*39 / 13 = 6 cm
Answer: 6 cm
