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3 years ago

Evaluate 15/k when k =3

Mathematics

2 answers:

Svetradugi [14.3K]3 years ago

3 0

Answer:

Step-by-step explanation:

If k is three than 15÷3 is 5

Over [174]3 years ago

3 0

Hello!

When a variable equals a number, you substitute in that number wherever the variable is. So, in this case, since k = 3, substitute in 3 wherever k appears in the equation.

15 / k

15 / 3

Now, divide 15 by 3. To do this, ask yourself how many times 3 goes into 15. It would be 5, as 3 + 3 + 3 + 3 + 3 = 15. (So essentially 5 3's go into 15, so it equals 5)

15 / 3 = 5

Therefore, your answer is 5.

Hope this helps!

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Hey i really need help with this. thank you:))

balandron [24]

Given:

$L=2\dfrac{1}{2}$ ft and $W=3\dfrac{2}{5}$ ft.

$P=2L+2W$

To find:

The value of P.

Solution:

We have,

$P=2L+2W$

Substituting $L=2\dfrac{1}{2}$ and $W=3\dfrac{2}{5}$ , we get

$P=2\times 2\dfrac{1}{2}+2\times 3\dfrac{2}{5}$

$P=2\times \dfrac{2(2)+1}{2}+2\times \dfrac{3(5)+2}{5}$

$P=2\times \dfrac{5}{2}+2\times \dfrac{17}{5}$

$P=5+\dfrac{34}{5}$

Taking LCM, we get

$P=\dfrac{5(5)+34}{5}$

$P=\dfrac{25+34}{5}$

$P=\dfrac{59}{5}$

$P=11\dfrac{4}{5}$

Therefore, the value of P is $11\dfrac{4}{5}$ ft.

7 0

3 years ago

10x^3-35x^2 please help me

marin [14]

Answer:

5x^2(2x-7)

Step-by-step explanation:

Hope this helps!

3 0

3 years ago

Tysm for the help! <3

Blizzard [7]

By using the given graph:

When x = -2, the value of the function is f(-2) = 1
When x = -0.5, the value of the function is f(-0.5) = 0.75
When x = 0, the value of the function is f(0) = 1.25
When x = 2.5, the value of the function is f(2.5) = 3
When x = 6, the value of the function is f(6) = 0

<h3></h3><h3>How to use the graph to find the values of the function?</h3>

Suppose that we want to find the value of the graphed function when x = a.

Then we first need to identify x = a in the horizontal axis.
Then we move upwards (or downwards) until we meet the curve of the function.
Now you can move horizontally towards the vertical axis, where you can read the y-value associated to the x-value.

Now we can do these steps for each of the wanted values.