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mariarad [96]
3 years ago
5

Evaluate 15/k when k =3

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
3 0

Answer:

5

Step-by-step explanation:

If k is three than 15÷3 is 5

Over [174]3 years ago
3 0

Hello!

When a variable equals a number, you substitute in that number wherever the variable is. So, in this case, since k = 3, substitute in 3 wherever k appears in the equation.

15 / k

15 / 3

Now, divide 15 by 3. To do this, ask yourself how many times 3 goes into 15. It would be 5, as 3 + 3 + 3 + 3 + 3 = 15. (So essentially 5 3's go into 15, so it equals 5)

15 / 3 = 5

Therefore, your answer is 5.

Hope this helps!

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Chris can type 490 words in 7 min how many works can he type PER min <br> You get 14 points
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<h2>Answer: 70 words per min</h2><h2 /><h2>Step-by-step explanation: We just divided 490 by 7 to get how many words he can type for 1 min!</h2>

5 0
3 years ago
An average light bulb manufactured by the Acme Corporation lasts 300 days with a standard deviation of 50 days. Assuming that bu
notsponge [240]

Answer:

1. 90% 2. 10% 3. 50%

Step-by-step explanation:

Standard Deviation (σ) = 50 days

Average/Mean (μ) = 300days

Probability that it would last more than 300 days = P(Bulb>300 days)

We will assume there are 365 days in a year.

P(Bulb>300 days)  implies that the bulb would

Using the normal equation;

z = standard/normal score = (x-μ)/σ where x is the value to be standardized

P(Bulb>300 days) implies x = 365 days

Therefore z = (365-300)/50 = 1.3

Using the normal graph for z=1.3, probability = 90%

2. P(Bulb<300 days) = 1 - P(Bulb>300 days)\

P(Bulb<300 days) = 1 - 0.9

P(Bulb<300 days)  = 10%

3. P(Bulb=300 days) implies z=0 since x=300

Using the normal graph for z=0, probability =50%

6 0
2 years ago
Suppose that 5 J of work is needed to stretch a spring from its natural length of 30 cm to a length of 39 cm.
vesna_86 [32]

Answer

given,

work = 5 J

spring stretch form 30 cm to 39 cm

W = \dfrac{1}{2}kx^2

x = 0.39 - 0.30 = 0.09 m

5 = \dfrac{1}{2}k\times 0.09^2

k = \dfrac{5\times 2}{0.09^2}

k = 1234.568 N/m

a) work when spring is stretched from  32 cm to 34 cm

x₂= 0.34 -0.30 = 0.04 m

x₁ = 0.32 - 0.30 = 0.02

W = \dfrac{1}{2}k(x_2^2-x_1^2)^2

W = \dfrac{1}{2}\times 1234.568 \times (0.04^2-0.02^2)^2

W = 0.741 J

b) F = k x

  25 = 1234.568 × x

     x = 0.0205 m

     x = 2.05 cm

3 0
3 years ago
What are the solutions to the system of equations graphed below?
PIT_PIT [208]

Answer:

(-3,-3) and at (0,6)

Step-by-step explanation:

The solution to the system of equations is where the graphs intersect

The graphs intersect at (-3,-3) and at (0,6)

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2 years ago
What is the vertex of the graph of the function below?
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