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cestrela7 [59]
3 years ago
9

It is the morning of the sandcastle-building competition at the beach. Dory has been looking forward to this event for months. A

ccording to her weather app, there is an 80% probability of high winds in her area today. Which of the following BEST describes the MOST likely way the probability was determined?
Mathematics
2 answers:
zvonat [6]3 years ago
6 0
One way is by comparing the weather for today as compared to the rest of the week or month.

Darina [25.2K]3 years ago
5 0

Answer:

B) Historically, in this area, high winds occur 80% of the time on days with similar meteorological conditions as today.

Explanation:

Meteorologists calculate the probability of certain weather conditions by dividing specific outcomes by the total number of possible outcomes. For example, to find out the probability of raining on a certain date, meteorologists use a large database which contains information about how many times it rained when the meteorological conditions were similar. If historically it rained during 5,000 days out of 8,000 total days that had a similar meteorological condition, then the probability of rain will be 5,000 / 8,000 = 62.5%

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An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
3 years ago
How to prove this using trig identities?
Pavlova-9 [17]

Step-by-step explanation:

tanB + cotB = (sinB)/(cosB) + (cosB)/(sinB)

 

                      = (sin2B + cos2B)/[(cosB)(sinB)]

 

                       = 1/[(cosB)(sinB)]

 

                        = (1/cosB)(1/sinB)

 

                        = (secB)(cscB)

7 0
3 years ago
If the height is 12 inches and the diameter is 16 inches, what is the volume?
tigry1 [53]

Answer:

V = πr²h

V = π(8)^2×12 r = ½diameter= 16/2=8

V = 64π×12

V= 64 × 3.14 ×12

V = 2,411.52 cubic inches.

Hope it helps!

4 0
2 years ago
Find the slope of the line that passes through the points (2, 1) and (-4, -5).
uysha [10]

the slope of the  is m= 1

5 0
3 years ago
FIND THE VALUE OF X.<br> 1.<br> (5x - 2)°<br> (3x + 4)
Archy [21]

Answer:

If 5x-2 = 3x+4, then x=3

Step-by-step explanation:

5x-2=3x+4

Add 2 to both sides, and you get 5x=3x+6. Subtract 3x from both sides, and you get 2x=6. Divide both sides by 2, and what's left is x=3. Hope this helps. :)

6 0
3 years ago
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