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Sergio [31]
3 years ago
6

a restaurant offers 7 appetizers and 11 main courses. in how many ways can a person order a two-course meal?

Mathematics
2 answers:
IgorC [24]3 years ago
4 0
There are 7 possibilities for appetisers and 11 for main courses, so the total number of combinations would be 7*11 = 77
True [87]3 years ago
3 0

Answer: 77

Step-by-step explanation:

From the question, for every 1 main course, the restaurant offers 7 appetizers that can go with it.

Since there are 11 main courses, that would mean for each one of the courses there will be 7 appetizers.

To get the number of ways a person can order a two-course meal, we multiply the appetizers by number of the courses. This will give :

7 × 11= 77

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23 marbles

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\huge\text{Hey there!}

\rm{-2x + 4 > 8}

\large\textsf{SUBTRACT  4 to BOTH SIDES}

\rm{-2x + 4 - 4 > 8 - 4}

\large\textsf{CANCEL puts 4 - 4 because that gives you 0}

\large\textsf{KEEP: 8 - 4 because that helps solve for the x-value}

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\rm{NEW\  EQUATION: -2x > 4}

\large\textsf{DIVIDE -2 to BOTH SIDES}

\mathsf{\dfrac{-2}{-2}>\dfrac{4}{-2}}

\mathsf{CANCEL\  out: \dfrac{-2}{-2}\  because\  that\  gives\  you\  1}

\mathsf{KEEP: \dfrac{4}{-2} \ because \ it \ helps \you \ compare\  to \  the \ x-value }

\mathsf{\dfrac{4}{-2} = \boxed{\bf -2}}

\rm{\bold{x < -2 }}

\rm{It\ is \ an\  O PENED \ circle \  shaded \  to \ the \ left \ side \ of \ the \ number  \ line}

\boxed{\boxed{\large\textsf{Answer: } \mathsf{\bf x < -2}}}\huge\checkmark

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~\frak{Amphitrite1040:)}

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