I dont know :(
i actually tried it but im not good with that :)
Answer:
v = 1/(1+i)
PV(T) = x(v + v^2 + ... + v^n) = x(1 - v^n)/i = 493
PV(G) = 3x[v + v^2 + ... + v^(2n)] = 3x[1 - v^(2n)]/i = 2748
PV(G)/PV(T) = 2748/493
{3x[1 - v^(2n)]/i}/{x(1 - v^n)/i} = 2748/493
3[1-v^(2n)]/(1-v^n) = 2748/493
Since v^(2n) = (v^n)^2 then 1 - v^(2n) = (1 - v^n)(1 + v^n)
3(1 + v^n) = 2748/493
1 + v^n = 2748/1479
v^n = 1269/1479 ~ 0.858
Step-by-step explanation:
There are 3³ possibilities for playing 3 rounds in rock paper scissors (3 choices in every round).
Draw a tree diagram of every round and (assuming that the three choices can be played in an random order as long as they are different), the options are 6.
P(RPS)=6/27=0.22
Hope I helped :)
I did the same thing and got 6 as well
<span>4 sweets cost 28
so 28/4 = 7 per sweet costs
So 7 sweets will be: 7 x 7 =49
Answer 7 sweets cost 49</span>
