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alexdok [17]
2 years ago
15

Find the value of x in the diagram

Mathematics
1 answer:
Dafna11 [192]2 years ago
4 0

Answer:

x = 135

Step-by-step explanation:

All the angles of a pentagon added up make 540 degrees.

540 - 60 = 480

480 - 150 = 330

330 - 120 = 210

210 - 75 = 135

x = 135

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A fair coin is tossed repeatedly with results Y0, Y1, Y2, . . . that are 0 or 1 with probability 1/2 each. For n ≥ 1 let Xn = Yn
Gekata [30.6K]

Answer:

False. See te explanation an counter example below.

Step-by-step explanation:

For this case we need to find:

P(X_{n+1} = | X_n =i, X_{n-1}=i') =P(X_{n+1}=j |X_n =i) for all i,i',j and for X_n in the Markov Chain assumed. If we proof this then we have a Markov Chain

For example if we assume that j=2, i=1, i'=0 then we have this:

P(X_{n+1} = | X_n =i, X_{n-1}=i') =\frac{1}{2}

Because we can only have j=2, i=1, i'=0 if we have this:

Y_{n+1}=1 , Y_n= 1, Y_{n-1}=0, Y_{n-2}=0, from definition given X_n = Y_n + Y_{n-1}

With i=1, i'=0 we have that Y_n =1 , Y_{n-1}=0, Y_{n-2}=0

So based on these conditions Y_{n+1} would be 1 with probability 1/2 from the definition.

If we find a counter example when the probability is not satisfied we can proof that we don't have a Markov Chain.

Let's assume that j=2, i=1, i'=2 for this case in order to satisfy the definition then Y_n =0, Y_{n-1}=1, Y_{n-2}=1

But on this case that means X_{n+1}\neq 2 and on this case the probability P(X_{n+1}=j| X_n =i, X_{n-1}=i')= 0, so we have a counter example and we have that:

P(X_{n+1} =j| X_n =i, X_{n-1}=i') \neq P(X_{n+1} =j | X_n =i) for all i,i', j so then we can conclude that we don't have a Markov chain for this case.

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3 years ago
5x - 2y = 10 x + 4y = 2
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Answer:

- 40

Step-by-step explanation:

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Answer:

??? I can't see the picture

Step-by-step explanation:

5 0
2 years ago
A function is blank a relation<br> *always<br> *sometimes<br> *never
zvonat [6]

Answer:

The correct answer is A.) Always

Step-by-step explanation:

A function is defined as a relation in which each element of the domain is mapped to one element of the range. In the definition itself, it is defined as a relation

I hope this helps you :)

-KeairaDickson

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