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MaRussiya [10]
3 years ago
14

If Oscar spins this spinner 100 times, approximately how many times will it land on blue?

Mathematics
2 answers:
Stella [2.4K]3 years ago
6 0

Answer:

50

Step-by-step explanation:

The chart is 50% of blue. Meaning, If you spin the spinner 100 times. it most likely will hit blue 50 times out of 100.

ziro4ka [17]3 years ago
3 0

50 because 50/100=2/4 and 2/4 is blue on the circle

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x=5

Step-by-step explanation:

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I need help with this math problem please.
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the 3rd one matches the number line

Step-by-step explanation:

the pointy part of the sign shows which way the line will go. if it has the line under the sign the dot on the number line is solid if not solid then it won't have a line

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3 0
3 years ago
Transform into y=mx + b form: - 2x + 6y = - 24
ziro4ka [17]

Answer:

y= 1/3 x-4

Step-by-step explanation:

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5 0
3 years ago
g find the 2 components of vector b = 2i + j - 3k, one parallel to a = 3i - j and another one perpendicular to a
nika2105 [10]

Answer:

The components of \vec{b} parallel and perpendicular to \vec {a} are \vec {b}_{\parallel} = \frac{3}{2}\,i-\frac{1}{2}\,j and \vec b _{\perp} = \frac{1}{2}\,i+\frac{3}{2}\,j-3\,k, respectively.

Step-by-step explanation:

Let be \vec b = 2\,i+j-3\,k and \vec a = 3\,i-j, the component of \vec b parallel to \vec a is calculated by the following expression:

\vec b_{\parallel} = (\vec b \bullet \hat{a}) \cdot \hat{a}

Where \hat{a} is the unit vector of \vec a, dimensionless and \bullet is the operator of scalar product.

The unit vector of \vec a is:

\hat{a} = \frac{\vec {a}}{\|\vec a\|}

Where \|\vec {a}\| is the norm of \vec a, whose value is determined by Pythagorean Theorem.

The component of \vec{b} parallel to \vec {a} is:

\|\vec {a}\| = \sqrt{3^{2}+(-1)^{2}+0^{2}}

\|\vec {a}\| = \sqrt{10}

\hat{a} = \frac{1}{\sqrt{10}} \cdot (3\,i-j)

\hat{a} = \frac{3}{\sqrt{10}}\,i -\frac{1}{\sqrt{10}} \,j

\vec{b}\bullet \hat{a} = (2)\cdot \left(\frac{3}{\sqrt{10}} \right)+(1)\cdot \left(-\frac{1}{\sqrt{10}} \right)+(-3)\cdot \left(0\right)

\vec b \bullet \hat{a} = \frac{5}{\sqrt{10}}

\vec b_{\parallel} = \frac{5}{\sqrt{10}}\cdot \left(\frac{3}{\sqrt{10}}\,i-\frac{1}{\sqrt{10}}\,j  \right)

\vec {b}_{\parallel} = \frac{3}{2}\,i-\frac{1}{2}\,j

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\vec{b}_{\perp} = \vec {b}-\vec {b}_{\parallel}

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\vec{b}_{\perp} = (2\,i+j-3\,k)-\left(\frac{3}{2}\,i-\frac{1}{2}\,j  \right)

\vec b _{\perp} = \frac{1}{2}\,i+\frac{3}{2}\,j-3\,k

4 0
3 years ago
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