Y2 -(-5y?) = ???????
2 answers:
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The first year, the amount is 40,000
the second year is 40000 + 4.2% of 40000, or 0.042 * 4000, so 40000+(0.042*4000)
common factoring that we get 40000(1 + 0.042), or just 40000(1.042)
in short, the starting amount is 40000, and to get the next term's value you'd use the "common ratio" of 1.042, namely the multiplier of 1.042.
for the third year it'll be 40000(1.042) + (0.042 *40000(1.042) ), again, common factoring that
40000(1.042)(1 + 0.042) or 40000(1.042)(1.042) or 40000(1.042)²
therefore,
the second year is 40000 + 4.2% of 40000, or 0.042 * 4000, so 40000+(0.042*4000)
common factoring that we get 40000(1 + 0.042), or just 40000(1.042)
in short, the starting amount is 40000, and to get the next term's value you'd use the "common ratio" of 1.042, namely the multiplier of 1.042.
for the third year it'll be 40000(1.042) + (0.042 *40000(1.042) ), again, common factoring that
40000(1.042)(1 + 0.042) or 40000(1.042)(1.042) or 40000(1.042)²
therefore,
The critical f-value when the sample size for the numerator and the denominator is given using a two-tailed test will be 0.12 and 14.88.
We have,
The sample size for the numerator = 6,
i.e.
Numerator degree of freedom = 6 - 1 = 5,
And,
The sample size for the denominator = 4,
i.e.
Denominator degree of freedom = 4 - 1 = 3
And,
We have to use a two-tailed test,
So,
The significance level = = 0.05
And,
Now,
The test follows the F-distribution with (5, 3) degrees of freedom,
Now,
Using the F-table at significance level 0.05 and check for given degrees of freedom,
We get,
Critical f-values : 0.12 and 14.88
Hence, we can say that the critical f-value when the sample size for the numerator and the denominator is given using a two-tailed test will be 0.12 and 14.88.
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