Answer:
Step-by-step explanation:
6 weeks is 42 days.
6 days/42 days = 1/7
Answer:
The inequality is
10+7x\leq 4010+7x≤40
Step-by-step explanation:
Let
x-----> the number of child tickets
we know that
10+7x\leq 4010+7x≤40 -----> inequality that represent the situation
Solve for x
7x\leq 40-107x≤40−10
7x\leq 307x≤30
x\leq 4.3x≤4.3
The maximum number of child tickets is 4
Let us say that:
x = cost of shorts
y = cost of slacks
z = cost of sports coat
From the given statements, we can create the following
equations:
eqtn 1: 3 x + y =
10.96
eqtn 2: 7 x + 2 y +
z = 30.40
eqtn 3: 4 x + z =
14.45
Rewrite eqtn 1 explicit to y:
y = 10.96 – 3 x -->
eqtn 4
Rewrite eqtn 3 explicit to z:
z = 14.45 – 4x -->
eqtn 5
Plug in the values of y (eqtn 4) and z (eqtn 5) to eqtn
2:
7 x + 2 (10.96 – 3 x) + 14.45 – 4 x = 30.40
7 x + 21.92 – 6 x + 14.45 – 4 x = 30.40
- 3 x + 36.37 = 30.40
- 3 x = - 5.97
x = 1.99
Eqtn 4:
y = 10.96 – 3 x
y = 10.96 – 3 (1.99)
y = 4.99
Eqtn 5:
z = 14.45 – 4x
z = 14.45 – 4 (1.99)
z = 6.49
Therefore each shirt cost $1.99, each slacks cost $4.99,
and each sports coat cost $6.49.
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For ADC you just add those two numbers. your answer would be D) 131
Answer:
y =47.5.
Step-by-step explanation:
First eliminate the fractions by multiplying through by the LCM of 7 and 3 which is 21:
21* 6[y-2]/7-21*12 = 21*2[y-7]/3
18(y - 2) - 252 = 14(y - 7)
18y -36 - 252 = 14y - 98
18y - 14y = -98 + 36 + 252
4y = 190
y = 190/4
y = 47.5.