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3 years ago

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michelle divided 1 pizza into equal slices to share with his friends.they ate the entire pizza. which expression could not repre

sent how michelle shared the pizza with her friends? a. 3\10+4\10+3\10 b. 1\10+1\10+1\0+6\10+1\10 c.3\10+3\10+3\10 d. 8\20+1\10+1\10 i think it is c 3\10+3\10+3\10 am i right? thanks for help.

1 answer:

user100 [1]3 years ago

3 0

The answer is c. you should know

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Rewrite each equation, then graph<br> the line<br> 6x + 3y = 12

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3 years ago

Evaluate the function f(x) at the given numbers (correct to six decimal places).

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Answer:

The function $f(x) = \frac{x^{2}-4\cdot x}{x^{2}-16}$ has the following set of solutions:

$f(4.1) = 0.506173$ , $f(4.05) = 0.503106$ , $f(4.01) = 0.500624$ , $f(4.001) = 0.500062$ , $f(4.0001) = 0.500006$ , $f(4.0001) = 0.500006$

$f(3.9) = 0.493671$ , $f(3.95) = 0.496855$ , $f(3.99) = 0.499374$ , $f(3.999) = 0.499937$ , $f(3.9999) = 0.499994$

Step-by-step explanation:

Let be $f(x) = \frac{x^{2}-4\cdot x}{x^{2}-16}$ , we proceed to simplify the expression by Algebraic means:

1) $\frac{x^{2}-4\cdot x}{x^{2}-16}$ Given

2) $\frac{x\cdot (x-4)}{(x-4)\cdot (x+4)}$ Associative, commutative and distributive properties/ $a^{2}-b^{2} = (a+b)\cdot (a - b)$

3) $\frac{x}{x + 4}$ Commutative, associative and modulative properties/Existence of multiplicative inverse/Result

Now we evaluate the function for each value:

$x = 4.1$

$f(4.1) = \frac{4.1}{4.1+4}$

$f(4.1) = 0.506173$

$x = 4.05$

$f(4.05) = \frac{4.05}{4.05 + 4}$

$f(4.05) = 0.503106$

$x = 4.01$

$f(4.01) = \frac{4.01}{4.01 + 4}$

$f(4.01) = 0.500624$

$x = 4.001$

$f(4.001) = \frac{4.001}{4.001+4}$

$f(4.001) = 0.500062$

$x = 4.0001$

$f(4.0001) = \frac{4.0001}{4.0001 + 4}$

$f(4.0001) = 0.500006$

$x = 3.9$

$f(3.9) = \frac{3.9}{3.9+4}$

$f(3.9) = 0.493671$

$x = 3.95$

$f(3.95) = \frac{3.95}{3.95+4}$

$f(3.95) = 0.496855$

$x = 3.99$

$f(3.99) = \frac{3.99}{3.99+4}$

$f(3.99) = 0.499374$

$x = 3.999$

$f(3.999) = \frac{3.999}{3.999 + 4}$

$f(3.999) = 0.499937$

$x = 3.9999$

$f(3.9999) = \frac{3.9999}{3.9999 + 4}$

$f(3.9999) = 0.499994$

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3 years ago

A metalworker has a metal alloy that is 20% copper and another alloy that is 60% copper. How many kilograms of each alloy shou

puteri [66]

<h3>Answer:</h3>

<u>20</u> kg of 20%
<u>80</u> kg of 60%

<h3>Step-by-step explanation:</h3>

I like to use a little X diagram to work mixture problems like this. The constituent concentrations are on the left; the desired mix is in the middle, and the right legs of the X show the differences along the diagonal. These are the ratio numbers for the constituents. Reducing the ratio 32:8 gives 4:1, which totals 5 "ratio units". We need a total of 100 kg of alloy, so each "ratio unit" stands for 100 kg/5 = 20 kg of constituent.

That is, we need 80 kg of 60% alloy and 20 kg of 20% alloy for the product.

_____

<em>Using an equation</em>

If you want to write an equation for the amount of contributing alloy, it works best to let a variable represent the quantity of the highest-concentration contributor, the 60% alloy. Using x for the quantity of that (in kg), the amount of copper in the final alloy is ...

... 0.60x + 0.20(100 -x) = 0.52·100

... 0.40x = 32 . . . . . . . . . . .collect terms, subtract 20

... x = 32/0.40 = 80 . . . . . kg of 60% alloy

... (100 -80) = 20 . . . . . . . .kg of 20% alloy

6 0

3 years ago