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mr_godi [17]
3 years ago
7

You want to drive traffic to a new landing page for a campaign, and want a web address that's short, easy to remember, trackable

, and reflective of your brand. Hootsuite supports you with:
1. vanity URLs
2. a batch of custom redirect links
3. enterprise URLs
4. custom top-level domain suffixes
Computers and Technology
1 answer:
Akimi4 [234]3 years ago
6 0

Hootsuite supports you with vanity URLs.

1. vanity URLs

<u>Explanation:</u>

Since the website webpage is landing on campaign, heavy network traffic is expected. Better to have multiple URL methods but it will not solve the purpose of heavy of network access of webpage or web site. Better to use vanity URLS methods to use heavy network traffic.

Vanity URLS means is customizable redirecting or rerouting by branding links or customized URL link. These type of vanity URLS by choosing hosting service and customize link been created. So end user can use link.

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Write a program that reads in an integer value for n and then sums the integers from n to 2 * n if n is nonnegative, or from 2 *
devlian [24]

Answer:

Following are the program in c++

First code when using for loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

for(i=n; i<=(2*n); i++)

{

sum1+= i;

}

}

else //  check if n  is negative

{

for(i=(2*n); i<=n; i++)

{

sum1+= i;

}

}

cout<<"The sum is:"<<sum1;

return 0;

Output

Enter the number: 1

The sum is:3

second code when using while loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

else //  check if n  is negative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

cout<<"The sum is:"<<sum1;

return 0;

}

Output

Enter the number: 1

The sum is:3

Explanation:

Here we making 2 program by using different loops but using same logic

Taking a user input in "n" variable.

if n is nonnegative then we iterate the loops  n to 2 * n and storing the sum in "sum1" variable.

Otherwise iterate a loop  2 * n to n and storing the sum in "sum1" variable.  Finally display  sum1 variable .

4 0
3 years ago
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