65/100 = 13/20
(divide by 5 on both sides)
Hope this helped!
Ok, First you have to find the GCF of 120 and 90. When I got the answer I got a GCF of 30. I got 30 by multiplying all the number prime numbers 120 and 90 had, 2×3×5=30 What I did next was divide thirty by the number of cracker and also by the number of can of juice.
120÷30= 4
90÷30= 3
So as you can see there could be a maximum 30 of kid's. Each of the kids would receive 4 cans of juice and 3 packs of cheese crackers.
I hope you enjoyed my explanation. :)
Answer:
(1,2)
Step-by-step explanation:
we know that
The rule of the transformation is equal to
(x, y) ------> (x + 3, y + 1)
Pre-image -----> Image
(x, y) ------> (4, 3)
so
x+3=4 ----> x=4-3=1
y+1=3 ---> y=3-1=2
therefore
The pre-image is the point (1,2)
This gives you three simultaneous equations:
6 = a + c
7 = 4a + c
1 = c
<u>c = 1
</u><u /><u />
If c =1,
6 = a + 1
<u>a = 5
</u><u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?
Okay so we get: subtract m + 8 from 5m + 11
5m + 11 = 16 + m or 16m
16m - 8 +m or 8m = 8m or 8 + m
