Can you guys please help me with this. I really need these answers or i will get a 0 :( please make sure they're correct! <3

Trapezoid W′X′Y′Z′ is the image of trapezoid WXYZ under a dilation through point C.

IRINA_888 [86]

Formula for scale factor
=image devide object
the answer is c

4 0

2 years ago

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What is the difference in Fahrenheit degrees between a temperature of 0C and a temperature of 15C?

slamgirl [31]

Answer:

$27^{\circ}F$

Step-by-step explanation:

Use formula

$F=1.8C+32$

to convert Celsius to Fahrenheit.

When $C_1=0^{\circ}C,$ then

$F_1=1.8\cdot 0+32\\ \\F_1=32^{\circ}F$

When $C_2=15^{\circ}C,$ then

$F_2=1.8\cdot 15+32\\ \\F_2=27+32=59^{\circ}F$

Difference:

$F_2-F_1=59^{\circ}F-32^{\circ}F=27^{\circ}F$

8 0

3 years ago

Write an equation of the line in point-slope form that passes through the given points.

iris [78.8K]

Answer:

Step-by-step explanation:

Want to practice with really hard SAT math problems to get a perfect math score? ... In a minute, we'll look at example questions and how to solve them, ... Next, take a gander at our individual math guides to help you shore up ...

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3 years ago

10.512×10^_3 write in proper scientific notation

IgorLugansk [536]

10512 is the answer since you just move the decimal place over to the right three times.

3 0

2 years ago

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A college student is taking two courses. The probability she passes the first course is 0.73. The probability she passes the sec

zhenek [66]

Answer:

b) No, it's not independent.

c) 0.02

d) 0.59

e) 0.57

f) 0.5616

Step-by-step explanation:

To answer this problem, a Venn diagram should be useful. The diagram with the information of Event 1 and Event 2 is shown below (I already added the information for the intersection but we're going to see how to get that information in the b) part of the problem)

Let's call A the event that she passes the first course, then P(A)=.73

Let's call B the event that she passes the second course, then P(B)=.66

Then P(A∪B) is the probability that she passes the first or the second course (at least one of them) is the given probability. P(A∪B)=.98

b) Is the event she passes one course independent of the event that she passes the other course?

Two events are independent when P(A∩B) = P(A) * P(B)

So far, we don't know P(A∩B), but we do know that for all events, the next formula is true:

P(A∪B) = P(A) + P(B) - P(A∩B)

We are going to solve for P (A∩B)

.98 = .73 + .66 - P(A∩B)

P(A∩B) =.73 + .66 - .98

P(A∩B) = .41

Now we will see if the formula for independent events is true

P(A∩B) = P(A) x P(B)

.41 = .73 x .66

.41 ≠.4818

Therefore, these two events are not independent.

c) The probability she does not pass either course, is 1 - the probability that she passes either one of the courses (P(A∪B) = .98)

1 - P(A∪B) = 1 - .98 = .02

d) The probability she doesn't pass both courses is 1 - the probability that she passes both of the courses P(A∩B)

1 - P(A∩B) = 1 -.41 = .59

e) The probability she passes exactly one course would be the probability that she passes either course minus the probability that she passes both courses.

P(A∪B) - P(A∩B) = .98 - .41 = .57

f) Given that she passes the first course, the probability she passes the second would be a conditional probability P(B|A)

P(B|A) = P(A∩B) / P(A)

P(B|A) = .41 / .73 = .5616

4 0

3 years ago