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Sav [38]
2 years ago
7

Can someone explain how you do fractions like adding them? And what rules they have to find the answer?

Mathematics
1 answer:
frozen [14]2 years ago
7 0

Answer:

Hope this image helps you. (sorry if it's tiny writing.)

Step-by-step explanation:

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Elizabeth is spinning a spinner with 5 equal sized sections. The sections are numbered 1, 1, 2, 2, 4. Which statement about the
Vinil7 [7]

Answer:

its d

Step-by-step explanation:

the options can be eliminated by using common sense.

8 0
3 years ago
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How do i solve the system of equations by graphing?<br>2x+y=7 <br>x-2y=6
scoray [572]

Answer:


Step-by-step explanation:

1. y = -2x + 7

2. Graph it (Mark (0, 7) or 7 on the y axis and go over one, down two, mark it and draw a line through both)

3. -2y = -x + 6

4. divide entire equation by 2 to isolate y

5. -y = -x + 3

6. multiply entire equation by -1 to make it positive

7. y=x+3

8. graph it (Mark (0,3) and go over one, down one, mark it and draw a line through both new points)

9. Where the lines intersect is your answer

8 0
3 years ago
Can you help me pls, this doesn't make any sense
Gala2k [10]
Area of the larger square = 12² = 144 cm²
Area of the smaller square = 7² = 49 cm²
Area of the section = 144-49 = 95 cm²
7 0
3 years ago
Someone help please, i cant solve this one :|
andrey2020 [161]

Answer:

i think its B

Step-by-step explanation:

4 0
3 years ago
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At a college, 69% of the courses have final exams and 42% of courses require research papers. Suppose that 29% of courses have a
laila [671]

Answer:

a) 0.82

b) 0.18

Step-by-step explanation:

We are given that

P(F)=0.69

P(R)=0.42

P(F and R)=0.29.

a)

P(course has a final exam or a research paper)=P(F or R)=?

P(F or R)=P(F)+P(R)- P(F and R)

P(F or R)=0.69+0.42-0.29

P(F or R)=1.11-0.29

P(F or R)=0.82.

Thus, the the probability that a course has a final exam or a research paper is 0.82.

b)

P( NEITHER of two requirements)=P(F' and R')=?

According to De Morgan's law

P(A' and B')=[P(A or B)]'

P(A' and B')=1-P(A or B)

P(A' and B')=1-0.82

P(A' and B')=0.18

Thus, the probability that a course has NEITHER of these two requirements is 0.18.

3 0
2 years ago
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